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3 years ago

HELP ME PLZ!!!! I'LL DO ABSOLUTELY ANYTHING, AND I MEAN ANYTHING!!!!!!

Physics

2 answers:

DiKsa [7]3 years ago

4 0

The amount of radiation that a human gets when traveling through space is very toxic this is something that makes it difficult for them to travel as well as the extreme temperatures.

Sergeu [11.5K]3 years ago

4 0

Answer:

There are so many things that make human travel difficult.

Here are some ideas ;

1) Air and Water -Taking water and oxygen from the Earth is very expensive and very difficult. (Note that if there is lots of water, oxygen can be made from the water. Also, if there is carbon dioxide, oxygen can be made.)

2) Food - people will need to grow their own food on another planet - transportation to and from Earth is, again, too expensive. Plants need carbon dioxide and sunlight (real sunlight is best; artificial lighting will work, too.)

3) Energy - Human settlements will need to create their own energy. Energy can be created using the sun.

Note that these powers have their own advantages and disadvantages

4) Radiation - Radiation is harmful for people, plants and animals. On Earth, we are protected by a magnetic field and an atmosphere. Some planets and moons have neither; some have only one or the other. Very few have both. Some planets have very strong magnetic fields that create even more radiation. Crazy right .

5) Gravity - planets or moons with a lesser gravitational pull than the Earth will result in astronauts having smaller bone and muscle mass, which is a serious problem if they are to come back to Earth. The closer a planet's gravity is to Earth, the less of a problem this is.

6) Atmosphere - Some planets have no atmosphere while some have atmospheres that will crush people(Woah ) .It's easier to deal with low-pressure rather than high-pressure, but both are dangerous if there is an air leak.

7) Distance - the further a planet is from Earth, the harder it is to.

8) Temperature - The hotter or colder a planet is, the more energy it will take to change the temperature(and im not really sure how ).

Explanation:

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What is the thermal energy of an object?

Vedmedyk [2.9K]

The total kinetic and potential energies

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3 years ago

To develop muscle tone, a woman lifts a 2.50 kg weight held in her hand. She uses her biceps muscle to flex the lower arm throug

Romashka [77]

To solve this problem we will use the concepts related to Torque as a function of the Force in proportion to the radius to which it is applied. In turn, we will use the concepts of energy expressed as Work, and which is described as the Torque's rate of change in proportion to angular displacement:

$\tau = Fr$

Where,

F = Force

r = Radius

Replacing we have that,

$\tau = Fr$

$\tau = 21cm (\frac{1m}{100cm})* 550N$

$\tau = 11.55Nm$

The moment of inertia is given by 2.5kg of the weight in hand by the distance squared to the joint of the body of 24 cm, therefore

$I = 0.25Kg\cdot m^2 +(2.5kg)(0.24m)^2$

$I = 0.394kg\cdot m^2$

Finally, angular acceleration is a result of the expression of torque by inertia, therefore

$\tau = I\alpha \rightarrow \alpha = \frac{\tau}{I}$

$\alpha = \frac{11.55}{0.394}$

$\alpha = 29.3 rad/s^2$

PART B)

The work done is equivalent to the torque applied by the distance traveled by 60 °° in radians $(\pi / 3)$ , therefore

$W = \tau \theta$

$W = 11.5* \frac{\pi}{3}$

$W = 12.09J$

4 0

3 years ago

LOTS OF POINTSA rocket of mass 40 000 kg takes off and flies to a height of 2.5 km as its engines produce 500 000 N of thrust.

Svetradugi [14.3K]

Answer:

i) E = 269 [MJ] ii)v = 116 [m/s]

Explanation:

This is a problem that encompasses the work and principle of energy conservation.

In this way, we establish the equation for the principle of conservation and energy.

$E_{k1}+W_{1-2}=E_{k2}\\where:\\E_{k1}= kinetic energy at moment 1\\W_{1-2}= work between moments 1 and 2.\\E_{k2}= kinetic energy at moment 2.$

$W_{1-2}= (F*d) - (m*g*h)\\W_{1-2}=(500000*2.5*10^3)-(40000*9.81*2.5*10^3)\\W_{1-2}= 269*10^6[J] or 269 [MJ]$

At that point the speed 1 is equal to zero, since the maximum height achieved was 2.5 [km]. So this calculated work corresponds to the energy of the rocket.

Er = 269*10^6[J]

ii ) With the energy calculated at the previous point, we can calculate the speed developed.

$E_{k2}=0.5*m*v^2\\269*10^6=0.5*40000*v^2\\v=\sqrt{\frac{269*10^6}{0.5*40000} }\\ v=116[m/s]$

8 0

3 years ago

A bottle rocket takes off with a = 34.5 m/s2. It

sergiy2304 [10]

Answer:3.4 seconds

Explanation:

Initial velocity(u)=0

acceleration=34.5m/s^2

Height(h)=200m

Time =t

h=u x t - (gxt^2)/2

200=0xt+(34.5xt^2)/2

200=34.5t^2/2

Cross multiply

200x2=34.5t^2

400=34.5t^2

Divide both sides by 34.5

400/34.5=34.5t^2/34.5

11.59=t^2

t^2=11.59

Take them square root of both sides

t=√(11.59)

t=3.4 seconds

8 0

3 years ago

which layer of the atmosphere is directly above the troposphere A. exosphere B. mesosphere C. troposphere or D. stratosphere

lozanna [386]

The layer above it would be D. the Stratosphere

8 0

3 years ago

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