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3 years ago

To find power we need to determine?

Physics

1 answer:

Lera25 [3.4K]3 years ago

6 0

Answer:

Work and time needed to the work

Explanation:

Power is defined as follows:

$P=\frac{W}{t}$

where

P is the power

W is the work done

t is the time needed to do the work

Since the work can also be rewritten as the product between force (F) and displacement (d):

W = F d

The power can be also rewritten as

$W=\frac{Fd}{t}$

But $\frac{d}{t}$ is equal to the velocity, v; so, power can be rewritten as product between force and velocity:

$P=Fv$

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Select the correct statement about osmolarity. a) Osmolarity measures the moles of solute per liter of solution. b) The contents

8090 [49]

Answer:

a) Osmolarity measures the moles of solute per liter of solution.

Explanation:

Osmolarity is defined as the number of moles of solute that contribute to the osmotic pressure, per liter of solution, of solution. That is, the measurement of the solute concentration. The prefix "osmo-" indicates the possible variation of the osmotic pressure in the cells, which will occur when the solution is introduced into the body.

7 0

3 years ago

A charged particle of mass 0.0050 kg is subjected to a 5.0 T magnetic field which acts at a right angle to its motion. If the pa

Irina18 [472]

Answer:

0.01 C

Explanation:

Applying,

F = qvBsinФ................ Equation 1

Where F = Force on the charged particle, q = charge on the particle, v = velocity, B = magnetic field, Ф = angle

Since the charged particle noves in a circle,

F = mv²/r................. Equation 2

Where m = mass of the particle, v = velocity of the particle, r = radius of the circle

Substitute equation 2 into equation 1

mv²/r = qvBsinФ

make q the subject of the equation

q = mv/(rBsinФ)............. Equation 3

Given: m = 0.005 kg, v = 2 m/s, r = 0.2 m, B = 5 T, Ф = 90° (Act at right angle)

Substitute these values into equation 3

q = (0.005×2)/(0.2×5×sin90°)

q = 0.01/(1)

q = 0.01 C

5 0

2 years ago

A trooper is moving due south along the freeway at a speed of 30.1 m/s when a red car passes the trooper. The red car moves with

romanna [79]

Answer:

The correct answer to the following question will be "41.87 m".

Explanation:

The given values are:

The speed of trooper = $30.1 \ m/s$

The velocity of red car = $45.4 \ m/s$

Now,

A red car goes as far as possible until the speed or velocity of the troops is the same as that of of the red car at

$t=\frac{45-30}{2.7}$ (∵ $time=\frac{distance}{time}$ )

$t=5.56 \ sec$

then,

The distance covered by trooper,

$t1=30\times 5.56+\frac{1}{2}\times 2.7\times (5.56)^2$

$=208.33 \ m$

The distance covered by red car,

= $45\times 5.56$

= $250.2 \ m$

Maximum distance = $250.2-208.33$

= $41.87 \ m$

6 0

3 years ago

You throw a ball downward from a window at a speed of 2.0m/s. How far has it fallen in 3 seconds?

bekas [8.4K]

Let's just assume that you throw the ball with an initial speed of 2 m/s instead of dropping it like free falling.
a=9.81 m/s^2
Vi= 2 m/s
t= 3 x

we use the formula
d = (Vi)(t) + (1/2)(a)(t)^2
d= (2)(3) + (1/2)(9.81)(9)
d=50.145 m

3 0

3 years ago

B.A certain piece of copper wire is determined to have a mass of 2.00 g per meter.

masha68 [24]

Answer:

14cm

Explanation:

Mass per gram of the piece of wire;

2g of the wire is found in 1m

Since

100cm = 1m;

So;

100cm of the wire contains 2g of the wire

To provide 0.28g

Since;

2g of wire is made up of 100cm

0.28g of wire will be contained in $\frac{100 x 0.28}{2}$ = 14cm

14cm of the wire will contain 0.28g

8 0

2 years ago