Answer:
The rise from A to B is 0.887
Solution:
As per the question:
The following reading of an inverted staff is given as:
A = 2.915
B = -2.028
Here, for inverted staff, the greater reading shows greater elevation and lesser reading shows lower elevation.
Thus
The rise from A to B is given as:
A - B = 2.915 - 2.028 = 0.887
Try this option, the answers are marked with colour.
A I think because sublimation is when something skips melting and goes directly to vapor
Answer:
0.11 m/s
Explanation:
From the question given above, the following data were obtained:
Initial displacement (d1) = 1.09 m
Final displacement (d2) = 2.55 m
Time (t) = 12.8 s
Average velocity =?
Next, we shall determine the total displacement (i.e change in displacement). This can be obtained as follow:
Initial displacement (d1) = 1.09 m
Final displacement (d2) = 2.55 m
Total displacement = d2 – d1
Total displacement = 2.55 – 1.09
Total displacement = 1.46 m
Finally, we shall determine the average velocity of the beetle. This can be obtained as follow:
Total Displacement = 1.46 m
Total time (t) = 12.8 s
Average velocity =?
Average velocity = Total Displacement / Total time
Average velocity = 1.46/12.8
Average velocity = 0.11 m/s
Thus, the average velocity of the beetle is 0.11 m/s
Answer: 0.08K
Explanation:
When temperature changes, the corresponding change in thermal energy of a gas is given by:
ΔE (thermal) = 3/2nRΔT
Defining the parameters:
ΔE (thermal) = Increase in thermal energy of the mono atomic gas = 1.0J
n = number of moles of the gas = 1.0mol
R = Ideal gas constant = 8.314J/mol/K
ΔT = change in temperature. This is what we need to find.
Rearranging the equation to make ΔT subject of the formula,
ΔT= 2 x ΔE (thermal) / (3 x n x R)
Therefore, ΔT = 2 x 1.0J / (3 x 1.0mol x 8.314J/mol/K)
ΔT = 2.0J / 24.942J/K
ΔT = 0.0802K
ΔT = 0.08K
The temperature change of 1.0mol of a monoatomic gas if its thermal energy is increased by 1.0J is 0.08K.
