Answer:

Solution:
As per the question:
Point charge, q = 
Test charge, 
Work done by the electric force, 
Now,
We know that the electric potential at a point is given by:

where
r = separation distance between the charges.
Also,
The work done by the electric force i moving a test charge from point A to B in an electric field:




Answer:
Lacks colored blood - Scorpion
Soft, unsegmented body - Octopus
A vertebrate - Bird
Lacks antennae - Starfish
Explanation:
Scorpion belongs to the Phylum Arthropoda of the Kingdom Animalia. All the organisms of this phylum lack coloured blood.
Octopus comes under the Phylum Molusca of the Kingdom Animalia. Soft, unsegmented body is the property of the organisms of this phylum.
Bird belongs to the Vertebrata class of the Phylum Chordata of Kingdom Animalia.
Starfish belongs to Echinodermata Phylum of the Kingdom Animalia. The organisms of this category do not posses antennae.
Answer:
a) 4.98m/s²
b) 481.66N
Explanation:
a) Using the Newtons second law of motion

m is the mass of the object
g is the acceleration due to gravity
Fm is the moving force acting along the plane
Ff is the frictional force opposing the moving froce
a is the acceleration of the skier
Given
m = 60kg
g = 9.8m/s²
= 35°
Ff = 38.5N
Required
acceleration of the skier a
Substituting into the formula;

Hence the acceleration of the skier is 4.98m/s²
b) The normal force on the skier is expressed as;
N = Wcosθ
N = mgcosθ
N = 60(9.8)cos 35°
N = 588cos 35°
N = 481.66N
Hence the normal force on the skier is 481.66N