Answer:
Half life is 6 years.
Explanation:
T½ = In2 / λ
Where λ = decay constant.
But N = No * e^-λt
Where N = final mass after a certain period of time
No = initial mass
T = time
N = 0.625g
No = 10g
t = 24 years
N = No* e^-λt
N / No = e^-λt
λ = -( 1 / t) In N / No (inverse of e is In. Check logarithmic rules)
λ = -(1 / 24) * In (0.625/10)
λ = -0.04167 * In(0.0625)
λ = -0.04167 * (-2.77)
λ = 0.1154
T½ = In2 / λ
T½ = 0.693 / 0.1154
T½ = 6.00 years.
The half life of radioactive cobalt-60 is 6 years
The mass percentage would be reduced but not as much as if it were a complete reaction ヽ༼ຈل͜ຈ༽ノ︵┻━┻ mark brainliest please
Our bodies digest the food we eat by mixing it with fluids (acids and enzymes) in the stomach. When the stomach digests food, the carbohydrate (sugars and starches) in the food breaks down into another type of sugar, called glucose.
<h3>
Answer:</h3>
322.7 kW
<h3>
Explanation:</h3>
- Power refers to the rate at which work is done.
- Therefore; Power = Work done ÷ time
- It is measured in joules per seconds or Watts
In this case, we are required to convert 0.3227 MW to kilowatts
We need to know that;
- 10^6 watts = 1 Megawatts(MW)
- 10^3 Watts = 1 kilowatts (kW)
Therefore;
10^3 kW = 1 MW
Therefore, the suitable conversion factor is 10^3kW/MW
Hence;
0.3227 MW is equivalent to;
= 0.3227 MW × 10^3kW/MW
= 322.7 kW
Thus, the peak power output is 322.7 kW