1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
koban [17]
3 years ago
13

Shana solves stoichiometry problems using the equation for the synthesis of water. Which interpretation of the balanced equation

would cause Shana to make a mistake? Two moles of hydrogen react with one mole of oxygen to form two moles of water. Two grams of hydrogen react with one gram of oxygen to form two grams of water. Two molecules of hydrogen react with one molecule of oxygen to form two molecules of water. Two liters of hydrogen react with one liter of oxygen to form two liters of water.
Chemistry
2 answers:
vampirchik [111]3 years ago
8 0

Answer : The wrong statement is, Two grams of hydrogen react with one gram of oxygen to form two grams of water.

Explanation :

Synthesis reaction : It is a type of reaction in which the reactants present in elemental state that reacts to give a single product.

It is represented as,

X+Y\rightarrow XY

where, X and Y are the reactants and XY is the product.

The balanced synthesis reaction of water will be,

2H_2+O_2\rightarrow 2H_2O

By the stoichiometry we can say that, 2 moles of hydrogen (H_2) react with 1 mole of oxygen (O_2) to form 2 moles of water (H_2O) as a single product.

Or we can say that,

2 molecules of hydrogen react with 1 molecule of oxygen to form 2 molecules of water.

Or,

2 liters of hydrogen react with 1 liter of oxygen to form 2 liters of water.

These three statements are correct.

But the statement, 2 grams of hydrogen react with 1 gram of oxygen to form 2 grams of water are incorrect statement.

Hence, the wrong statement is, Two grams of hydrogen react with one gram of oxygen to form two grams of water.

skelet666 [1.2K]3 years ago
6 0

Answer: Two grams of hydrogen react with one gram of oxygen to form two grams of water.

You might be interested in
A box has a volume of 45m3 and is filled with air held at 25∘C and 3.65atm. What will be the pressure (in atmospheres) if the sa
Marina CMI [18]

Answer:

Given:

  • Initial pressure: 3.65\; \rm atm.
  • Volume was reduced from 45\; \rm m^{3} to 5.0\; \rm m^{3}.
  • Temperature was raised from 25\; ^\circ \rm C to 35\; ^\circ \rm C.

New pressure: approximately 3.4\times 10\; \rm atm (34\; \rm atm.) (Assuming that the gas is an ideal gas.)

Explanation:

Both the volume and the temperature of this gas has changed. Consider the two changes in two separate steps:

  • Reduce the volume of the gas from 45\; \rm m^{3} to 5.0\; \rm m^{3}. Calculate the new pressure, P_1.
  • Raise the temperature of the gas from 25\; ^\circ \rm C to 35\; ^\circ \rm C. Calculate the final pressure, P_2.

By Boyle's Law, the pressure of an ideal gas is inversely proportional to the volume of this gas (assuming constant temperature and that no gas particles escaped or was added.)

For this gas, V_0 = 45\; \rm m^{3} while V_1 = 5.0\; \rm m^{3}.

Let P_0 denote the pressure of this gas before the volume change (P_0 = 3.65\; \rm atm.) Let P_1 denote the pressure of this gas after the volume change (but before changing the temperature.) Apply Boyle's Law to find the ratio between P_1\! and P_0\!:

\displaystyle \frac{P_1}{P_0} = \frac{V_0}{V_1} = \frac{45\; \rm m^{3}}{5.0\; \rm m^{3}} = 9.0.

In other words, because the final volume is (1/9) of the initial volume, the final pressure is 9 times the initial pressure. Therefore:

\displaystyle P_1 = 9.0\times P_0 = 32.85\; \rm atm.

On the other hand, by Amonton's Law, the pressure of an ideal gas is directly proportional to the temperature (in degrees Kelvins) of this gas (assuming constant volume and that no gas particle escaped or was added.)

Convert the unit of the temperature of this gas to degrees Kelvins:

T_1 = (25 + 273.15)\; \rm K = 298.15\; \rm K.

T_2 = (35 + 273.15)\; \rm K = 308.15\; \rm K.

Let P_1 denote the pressure of this gas before this temperature change (P_1 = 32.85\; \rm atm.) Let P_2 denote the pressure of this gas after the temperature change. The volume of this gas is kept constant at V_2 = V_1 = 5.0\; \rm m^{3}.

Apply Amonton's Law to find the ratio between P_2 and P_1:

\displaystyle \frac{P_2}{P_1} = \frac{T_2}{T_1} = \frac{308.16\; \rm K}{298.15\; \rm K}.

Calculate P_2, the final pressure of this gas:

\begin{aligned} P_2 &= \frac{308.15\; \rm K}{298.15\; \rm K} \times P_1 \\ &= \frac{308.15\; \rm K}{298.15\; \rm K} \times 32.85\; \rm atm \approx 3.4 \times 10\; \rm atm\end{aligned}.

In other words, the pressure of this gas after the volume and the temperature changes would be approximately 3.4\times 10\; \rm atm.

8 0
3 years ago
How do plants play an important role in preventing wind erosion
Assoli18 [71]
By holding down the soil
8 0
4 years ago
Read 2 more answers
a sample of gas initially occupies 5.50 liter at a pressure of 0.750 atm at 13.0 C. what will the temperture change to 22.5 C an
sergey [27]

Answer:

The pressure will be 2.84 atm

Explanation:

The gas laws are a set of chemical and physical laws that allow us to determine the behavior of gases in a closed system. The parameters evaluated in these laws are pressure, volume, temperature and moles.

Boyle's law indicates that the volume is inversely proportional to the pressure: if the pressure increases, the volume decreases and if the pressure decreases, the volume increases. Boyle's law is expressed mathematically as:

P * V = k

On the other hand, Charles's law indicates that with increasing temperature, the volume of the gas increases and with decreasing temperature, the volume of the gas decreases. That is, they are directly proportional. This is expressed mathematically as:

\frac{V}{T} =k

Finally, the Gay-Lussac law says that at constant volume, the pressure of the gas is directly proportional to its temperature. Mathematically, it is expressed as:

\frac{P}{T} =k

Combined law equation is the combination of three gas laws called Boyle's, Charlie's and Gay-Lusac's law:

\frac{P*V}{T}=k

When you want to study two different states, an initial and a final one of a gas, you can use the following expression:

\frac{P1*V1}{T1}=\frac{P2*V2}{T2}

In this case:

  • P1= 0.750 atm
  • V1= 5.50 L
  • T1= 13 C= 286 K (being 0 C=273 K)
  • P2=?
  • V2= 1.50 L
  • T2= 22.5 C=295.5 K

Replacing:

\frac{0.750 atm*5.50 L}{286 K}= \frac{P2*1.50 L}{295.5 K}

Solving:

P2=\frac{295.5K}{1.50L} *\frac{0.750 atm*5.50 L}{286 K}

P2= 2.84 atm

<u><em>The pressure will be 2.84 atm</em></u>

8 0
4 years ago
How to extract salt from salt water
Vadim26 [7]

Answer:

Put the water out in the sun and the water will evaporate.  

Explanation:

7 0
2 years ago
Stimulation optimization helps
EastWind [94]
Optimization helps you make better choices when you have all the data, and simulation helps you understand the possible outcomes when you don’t. Frontline Solvers enable you to combine these analytic methods, so you can make better choices for decisions you do control, taking into account the range of potential outcomes for factors you don’t control.
5 0
3 years ago
Other questions:
  • If the o2 is collected over water at 25 c (298 k) and 724.0 mm hg total pressure, how many mols o2 will a 1.00 l sample of colle
    12·1 answer
  • Pb12 (s) = Pb+2 (aq)<br> +<br> 2 ]- (aq)
    5·1 answer
  • How do deep currents form ???
    8·1 answer
  • What does this quote mean to you? <br> "You may need to fight a battle more then once to win."
    5·2 answers
  • YOU MUST SHOW ALL STEPS OF THE G.U.E.S.S. METHOD CORRECTLY. NO UNITS=WRONG ANSWER
    9·1 answer
  • A sample of xenon gas occupies 1.90L at 251 kPa and -18°C. What was the temperature of the xenon if the gas originally measured
    6·1 answer
  • Consider the reaction: NaNO3(s) + H2SO4(l) NaHSO4(s) + HNO3(g) ΔH° = 21.2 kJ
    8·1 answer
  • The liter is a measurement of which of the following qualities volume,teampature,mass,density
    14·1 answer
  • Would happen if a positive charge was placed between the two charges and allowed to move?
    6·1 answer
  • The electron configuration of a Mn atom is 1s2 2s2 2p6 3s2 3p6 4s2 3d5. Determine the number of unpaired electrons in the Mn ato
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!