<span>Reaction: CI2 + H2O ----> HCIO + HCI
Oxidations states:
The oxitation state of Cl2 = 0, because the oxidation state of an atom alone or a molucule with one kind of atom is always 0.
The
oxidation state of Cl in HClO is +1 because the oxidation state of H is
+ 1, the oxidation state of O is - 2, and the molecule is neutral, so
+1 + 1 - 2 = 0
The oxidation state of Cl in HCl is - 1, because the oxidation state of H is +1 and the molecule is neutral, so - 1 + 1 = 0.
Also,
you shall remember that when an atom increases its oxidation state is
is oxidized and when an atoms reduces its oxidations state it is
reduced.
With that you conclude that the right option is the last statement: </span>Cl
has an oxidation number of 0 in Cl2. It is then reduced to CI- with an
oxidation number of –1 in HCl and is oxidized to Cl+ with an oxidation
number +1 in HClO.
Explanation:
<em>Phys</em><em>ical</em><em> </em><em>Change </em><em>is</em><em> </em><em>a</em><em> </em><em>type </em><em>of </em><em>change </em><em>where</em><em> </em><em>by</em><em> </em><em>no</em><em> </em><em>new</em><em> </em><em>chemical </em><em>substance</em><em> </em><em>is</em><em> </em><em>formed</em><em>.</em><em> </em><em>Physical</em><em> </em><em>changes</em><em> </em><em>are </em><em>reversible</em><em>.</em><em> </em><em>whilst</em><em> </em><em>Chemical</em><em> </em><em>change </em><em>is</em><em> </em><em>a</em><em> </em><em>change </em><em>where </em><em>new</em><em> </em><em>chem</em><em>i</em><em>c</em><em>a</em><em>l</em><em> </em><em>substance</em><em> </em><em>is</em><em> </em><em>always</em><em> </em><em>formed.</em><em> </em><em>Chemical</em><em> </em><em>changes </em><em>are</em><em> </em><em>usually</em><em> </em><em>irreversible</em><em>.</em>
<em>Examples </em><em>of </em><em>Physical</em><em> </em><em>Change</em><em> </em><em>include</em><em>;</em>
<em>Melting</em><em> </em><em>of</em><em> </em><em>Ice</em>
<em>Melting</em><em> </em><em>of </em><em>Candle</em>
<em>Grinding </em><em>of </em><em>chalk</em>
<em>Magnetization </em><em>of</em><em> </em><em>Iron</em>
<em>Examples</em><em> </em><em>of</em><em> </em><em> </em><em>Chemical</em><em> </em><em>Change</em><em> </em><em>includes</em><em>;</em>
<em>Cooking</em><em> </em><em>of </em><em>food</em>
<em>Rusting </em><em>of </em><em>Iron</em>
<em>Burning</em><em> </em><em>of </em><em>Charcoal</em>
Answer:
The volume increases by 100%.
Explanation:
<u>Step 1:</u> Data given
Number of moles ideal gas = 1 mol
Initial temperature = 305 K
Final temperature = 32°C + 273.15 = 305.15 K
Initial pressure = 2 atm
final pressure = 101 kPa = 0.996792 atm
R = gasconstant = doesn't change
V1 = initial volume
V2= the final volume
<u>Step 2: </u>Calculate volume of original gas
P*V = n*R*T
(P*V)/ T = constante
(P1 * V1) / T1 = (P2 * V2)/ T2
In this situation we have:
(2atm * V1)/ 305 = (0.996792 *V2) / 305.15
0.006557*V1 = 0.003266*V2
V2 = 2*V1
We see that the final volume is twice the initial volume. So the volume gets doubled. The volume increases by 100%.
Answer:
The rate is a mathematical relationship obtained by comparing reaction rate with reactant concentrations.
<span>It makes no difference which reactant is placed first, a strong acid combined stoichiometrically with a strong base will produce a neutral solution. Due to hydrolysis, a weak acid and strong base produce a basic solution when combined stoichiometrically, and a weak base and strong acid produce an acidic solution when combined stoichiometrically
Mark as brainlist please if correct! BTW have a blessed day!</span>