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Sophie [7]
3 years ago
12

When entering coefficients to balance equations, recall that just writing the symbol implies "1." Therefore, if a coefficient of

"1" is required, choose "blank" for that box.
Balance the following reaction.

C2H5 + O2 → CO2 + H2O
Chemistry
2 answers:
Free_Kalibri [48]3 years ago
8 0
The balanced equation for the combustion reaction is as follows
4C₂H₅ + 13O₂ --> 8CO₂ + 10H₂O
coefficients for the reactants and products are 
C₂H₅ - 4
O₂ - 13
CO₂ - 8
H₂O - 10
bixtya [17]3 years ago
8 0

The given equation is :

C₂H₆ + O₂ → CO₂ + H₂O

An equation is said to be balanced if the number of atoms of one kind is equal in both the reactants as well as the product side. here we have:

Reactants             Products

C = 2                      C= 1

H = 5                      H = 2

O = 2                      O = 3

The balanced equation would be as follows:

2C₂H₆ + 7O₂ → 4CO₂ + 6H₂O

Reactants             Products

C = 4                      C= 4

H = 12                      H = 12

O = 14                     O = 14


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In the disproportionation reaction CI2 + H2Omc021-1.jpgHCIO + HCI, what describes the oxidation states of the substance Cl?
Sophie [7]
<span>Reaction: CI2 + H2O    ---->  HCIO + HCI

Oxidations states:

The oxitation state of Cl2 = 0, because the oxidation state of an atom alone or a molucule with one kind of atom is always 0.

The oxidation state of Cl in HClO is +1 because the oxidation state of H is + 1, the oxidation state of O is - 2, and the molecule is neutral, so  +1 + 1 - 2 = 0

The oxidation state of Cl in HCl is - 1, because the oxidation state of H is +1 and the molecule is neutral, so - 1 + 1 = 0.

Also, you shall remember that when an atom increases its oxidation state is is oxidized and when an atoms reduces its oxidations state it is reduced.

With that you conclude that the right option is the last statement: </span>Cl has an oxidation number of 0 in Cl2. It is then reduced to CI- with an oxidation number of –1 in HCl and is oxidized to Cl+ with an oxidation number +1 in HClO.
8 0
4 years ago
Differentiate between physical and chemical change​
Andrei [34K]

Explanation:

<em>Phys</em><em>ical</em><em> </em><em>Change </em><em>is</em><em> </em><em>a</em><em> </em><em>type </em><em>of </em><em>change </em><em>where</em><em> </em><em>by</em><em> </em><em>no</em><em> </em><em>new</em><em> </em><em>chemical </em><em>substance</em><em> </em><em>is</em><em> </em><em>formed</em><em>.</em><em> </em><em>Physical</em><em> </em><em>changes</em><em> </em><em>are </em><em>reversible</em><em>.</em><em> </em><em>whilst</em><em> </em><em>Chemical</em><em> </em><em>change </em><em>is</em><em> </em><em>a</em><em> </em><em>change </em><em>where </em><em>new</em><em> </em><em>chem</em><em>i</em><em>c</em><em>a</em><em>l</em><em> </em><em>substance</em><em> </em><em>is</em><em> </em><em>always</em><em> </em><em>formed.</em><em> </em><em>Chemical</em><em> </em><em>changes </em><em>are</em><em> </em><em>usually</em><em> </em><em>irreversible</em><em>.</em>

<em>Examples </em><em>of </em><em>Physical</em><em> </em><em>Change</em><em> </em><em>include</em><em>;</em>

<em>Melting</em><em> </em><em>of</em><em> </em><em>Ice</em>

<em>Melting</em><em> </em><em>of </em><em>Candle</em>

<em>Grinding </em><em>of </em><em>chalk</em>

<em>Magnetization </em><em>of</em><em> </em><em>Iron</em>

<em>Examples</em><em> </em><em>of</em><em> </em><em> </em><em>Chemical</em><em> </em><em>Change</em><em> </em><em>includes</em><em>;</em>

<em>Cooking</em><em> </em><em>of </em><em>food</em>

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<em>Burning</em><em> </em><em>of </em><em>Charcoal</em>

3 0
3 years ago
What is the effect of the following on the volume of 1 mol of an ideal gas? The temperature changes from 305 K to 32°C and the p
ryzh [129]

Answer:

The volume increases by 100%.

Explanation:

<u>Step 1:</u> Data given

Number of moles ideal gas = 1 mol

Initial temperature = 305 K

Final temperature = 32°C + 273.15 = 305.15 K

Initial pressure = 2 atm

final pressure = 101 kPa = 0.996792 atm

R = gasconstant = doesn't change

V1 = initial volume

V2= the final volume

<u>Step 2: </u>Calculate volume of original gas

P*V = n*R*T

(P*V)/ T = constante

(P1 * V1) / T1 = (P2 * V2)/ T2

In this situation we have:

(2atm * V1)/ 305  = (0.996792 *V2) / 305.15

0.006557*V1 = 0.003266*V2

V2 = 2*V1

We see that the final volume is twice the initial volume. So the volume gets doubled. The volume increases by 100%.

7 0
3 years ago
If we know this is a second-order reaction, what is the rate law?
Pavel [41]

Answer:

The rate is a mathematical relationship obtained by comparing reaction rate with reactant concentrations.

6 0
4 years ago
Which of the following pairs of reactants is not correctly listed with its product solution? A. Strong acid-strong base reactant
gizmo_the_mogwai [7]
<span>It makes no difference which reactant is placed first, a strong acid combined stoichiometrically with a strong base will produce a neutral solution. Due to hydrolysis, a weak acid and strong base produce a basic solution when combined stoichiometrically, and a weak base and strong acid produce an acidic solution when combined stoichiometrically

Mark as brainlist please if correct! BTW have a blessed day!</span>
5 0
3 years ago
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