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3 years ago

How does the water cycle contribute to the "brown ocean" effect?

Chemistry

1 answer:

exis [7]3 years ago

5 0

Answer:

Hurricanes and tropical storms gain their power from heated water evaporating from the ocean.

Explanation:

<h3>Brown Water Effect </h3>

The brown ocean effect is an observed weather phenomenon involving some tropical cyclones after landfall. Normally, hurricanes and tropical storms lose strength when they make landfall, but when the brown ocean effect is in play, tropical cyclones maintain strength or even intensify over land surfaces.

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Describe, in terms of valence electrons, how the chemical bonds form in the substance

Talja [164]

Based on the picture, the way that chemical bonds form in the substance is :
K loses an electron and Br gains an electron.
This created difference in charges, which create attraction

hope this helps

7 0

4 years ago

Write a balanced half-reaction for the reduction of dichromate ion to chromium ion in acidic aqueous solution. Be sure to add ph

Serhud [2]

Answer:

The balanced half-reaction for the reduction of dichromate ion to chromium ion in acidic aqueous solution:

$Cr_2O_7^{2-}(aq)+14H^+(aq)+6e^-\rightarrow 2Cr^{3+}(aq)+7H_2O(l)$

Explanation:

The reaction :

$Cr_2O_7^{2-}\rightarrow Cr^{3+}$

Balancing of reaction in an acidic medium:

Step 1: Balance the atoms in the reaction:

$Cr_2O_7^{2-}(aq)\rightarrow 2Cr^{3+}(aq)$

Step 2: Balance oxygen atom by adding water on the side where no oxygen or less oxygen atom is present;

$Cr_2O_7^{2-}(aq)\rightarrow 2Cr^{3+}(aq)+7H_2O(l)$

Step 3: Balance the hydrogen atom by adding hydrogen ions on the side where water is absent:

$Cr_2O_7^{2-}(aq)+14H^+(aq)\rightarrow 2Cr^{3+}(aq)+7H_2O(l)$

Step 4: Now balance charge by adding electrons on the side where more positive charge is present

$Cr_2O_7^{2-}(aq)+14H^+(aq)+6e^-\rightarrow 2Cr^{3+}(aq)+7H_2O(l)$

The balanced half-reaction for the reduction of dichromate ion to chromium ion in acidic aqueous solution:

$Cr_2O_7^{2-}(aq)+14H^+(aq)+6e^-\rightarrow 2Cr^{3+}(aq)+7H_2O(l)$

6 0

3 years ago

Determine if the individual bonds in each compound are polar or nonpolar.

almond37 [142]

Answer:

See explanation

Explanation:

For SCl2

S = 2.8, Cl = 3.16 difference = 0.4 polar

H2S

H = 2.2 S= 2.8 difference = 0.6 polar

CF4

C = 2.55, F= 3.98 difference = 1.43

This compound is nonpolar irrespective of the difference in electronegativity because the molecule is symmetrical

PCl5

P= 2.19, Cl= 3.16 difference = 0.97

This compound is nonpolar irrespective of the difference in electronegativity because the molecule is symmetrical

CH4

C = 2.55 H = 2.2 difference = 0.35 the molecule is nonpolar

CaBr2

Ca= 1 Br= 2.96 difference = 1.96

The compound is not just polar but ionic in nature due to large electronegativity difference between the bonding atoms

SF2

S = 2.8 F= 3.98 difference = 1.18

The molecule is polar

CO2

C= 2.55 O= 3.44 difference = 0.89

This compound is nonpolar irrespective of the difference in electronegativity because the molecule is symmetrical

NH3

N= 3.04 H = 2.2 difference =0.84

The molecule is polar

NaS

Na= 0.93 S = 2.8 difference = 1.87

The compound is not just polar but ionic in nature due to large electronegativity difference between the bonding

4 0

3 years ago

What are extensive properties of Oxygen?

d1i1m1o1n [39]

The extensive property of Oxygen is Volume, Enthalpy, Entropy.

5 0

3 years ago

You need to produce a buffer solution that has a pH of 5.00. You already have a solution that contains 10. mmolmmol (millimoles)

weeeeeb [17]

Answer : The millimoles of acetate need to add to this solution will be, 18.2 mmol

Explanation :

For acetic acid, $pK_a=4.74$

Moles of of acetic acid = 10 mmol

pH = 5.00

Using Henderson Hesselbach equation :

$pH=pK_a+\log \frac{[Salt]}{[Acid]}$

Now put all the given values in this expression, we get:

$5.00=4.74+\log (\frac{Salt}{10})$

$Salt=18.2mmol$

Thus, the millimoles of acetate need to add to this solution will be, 18.2 mmol

3 0

4 years ago