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3 years ago

11

The quotient of s and three

1 answer:

Doss [256]3 years ago

7 0

Answer:

s/3

Step-by-step explanation:

The quotient means you divide the two values.

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I need HELP Quick!!!

kow [346]

D. the values of x is 8

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4 years ago

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What are the zeros of the quadratic function f(x) = 2x2 + 8x – 3? x = –2 – StartRoot StartFraction 11 Over 2 EndFraction EndRoot

Phantasy [73]

Answer:

The zeros are

$x=-2+\frac{\sqrt{22}}{2}$

$x=-2-\frac{\sqrt{22}}{2}$

Step-by-step explanation:

we have

$f(x)=2x^{2}+8x-3$

we know that

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

Equate the function to zero

$2x^{2} +8x-3=0$

so

$a=2\\b=8\\c=-3$

substitute in the formula

$x=\frac{-8\pm\sqrt{8^{2}-4(2)(-3)}} {2(2)}$

$x=\frac{-8\pm\sqrt{88}} {4}$

$x=\frac{-8\pm2\sqrt{22}} {4}$

$x=-2\pm\frac{\sqrt{22}}{2}$

therefore

$x=-2+\frac{\sqrt{22}}{2}$

$x=-2-\frac{\sqrt{22}}{2}$

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4 years ago

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Fifty people put there name

Leokris [45]

Answer:Male 60% Female 40%

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3 years ago

consider the function f(x) = x2 2x – 15. what are the x-intercepts of the function? left-most x-intercept: ( , 0) right-most x-i

eimsori [14]

we have

$f(x)=x^{2} +2x-15$

we know that

The x-intercept is the value of x when the value of the function is equal to zero

so

in this problem

Find the roots of the function

equate the function to zero

$x^{2} +2x-15=0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$x^{2} +2x=15$

Complete the square. Remember to balance the equation by adding the same constants to each side

$x^{2} +2x+1=15+1$

$x^{2} +2x+1=16$

Rewrite as perfect squares

$(x+1)^{2}=16$

Square root both sides

$(x+1)=(+/-)\sqrt{16}$

$(x+1)=(+/-)4$

$x=-1(+/-)4$

$x1=-1+4=3$

$x2=-1-4=-5$

$x^{2} +2x-15=(x-3)(x+5)$

therefore

<u>the answer is</u>

the x-intercepts are the points $(3,0)$ and $(-5,0)$

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3 years ago

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I really need this help

IRISSAK [1]

Answer:

area: 454.2 sq.cm

perimeter: 77.7 cm

Step-by-step explanation:

to find area, find the area of all the separate shapes and add them together:

semi-circle:

radius is 12 cm

area = $\frac{\pi (12)^2\\}{2}$ = 226.2 sq.cm

separate the trapezoid into two right triangles and a rectangle.

area for triangles:

$\frac{1}{2}$ (5)(12) = 30

30 x 2 = 60 sq.cm (since there are two triangles)

area for rectangle:

12 x 14 = 168 sq.cm

area of whole shape: 226.2 + 60 + 168 = 454.2 sq.cm

for perimeter, just add the length of the exterior sides together.

we have some unknown sides, such as the semicircle and the sides of the trapezoid

we can find the hypotenuse of the triangles we used earlier to find the sides of the trapezoid with pythagorean theorem

$5^2 + 12^2 = c^2$

$25 + 144 = c^2$

$169 = c^2$

$\sqrt{169} =\sqrt{c^2}$

c = 13 cm

to find the outside perimeter of the semi-circle, solve as if you were finding the circumference of a normal circle and divide it in half

$\frac{2\pi12}{2}$ = 37.7 cm

now add it all up:

14 + 13 + 13 +37.7 = 77.7

3 0

3 years ago