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FinnZ [79.3K]
3 years ago
7

Based upon the intermolecular forces present, rank the following substances according to the expected boiling point for the subs

tance.
Rank from highest to lowest boiling point. To rank items as equivalent, overlap them.
HCl, NaCl, N2, H2O
Chemistry
1 answer:
Trava [24]3 years ago
8 0

Answer: NaCl>HCl&H2O> N2

Explanation:

NaCl, as an ionic substance has a very high boiling point as expected. However, the boiling points of HCl and H2O depend on the relative concentration of the HCl and water, at 20% HCl, it boils at almost the same temperature as water due to extensive intermolecular hydrogen bonding. N2 comprises only of Vanderwaals forces hence it has the least boiling point.

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An air tight freezer measures 4 mx 5 m x 2.5 m high. With the door open, it fills with 22 °C air at 1 atm pressure.
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Answer:

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(b) Pressure = 93772 Pa or 0.703 mmHg

(c) Force needed to open the door =  15106 N

Explanation:

(a) The density of the air at 22 deg C and 1 atm can be calculated using the Ideal Gas Law:

\rho_{air}=\frac{P}{R*T}

First, we change the units of P to Pa and T to deg K:

P=1 atm * \frac{101,325Pa}{1atm}=101,325 Pa\\\\ T=22+273.15=293.15^{\circ}K

Then we have

\rho_{air}=\frac{P}{R*T}=\frac{101325Pa}{287.05 J/(kg*K)*293.15K} =1.204 \frac{kg}{m3}

(b) To calculate the change in pressure, we use again the Ideal Gas law, expressed in another way:

PV=nRT\\P/T=nR/V=constant\Rightarrow P_{1}/T_{1}=P_{2}/T_{2}\\\\P_{2}=P_{1}*\frac{T_{2}}{T_{1}}=101325Pa*\frac{7+273.15}{22+273.15}=101,325Pa*0.9254=93,772Pa\\\\P2=93,772 Pa*\frac{1mmHg}{133,322Pa}= 0.703 mmHg

(c) To calculate the force needed to open we have to multiply the difference of pressure between the inside of the freezer and the outside and the surface of the door. We also take into account that Pa = N/m2.

F=S_{door}*\Delta P=2m^{2} *(101325Pa - 93772Pa)=2m^{2} *7553N/m2=15106N

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2 years ago
One atom of an element A =6.644 *10^-23 gm. calculate the no. of gram atom in 80 kg of it.<br><br>​
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Answer:

5.3152*10^-24

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