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FinnZ [79.3K]
4 years ago
7

Based upon the intermolecular forces present, rank the following substances according to the expected boiling point for the subs

tance.
Rank from highest to lowest boiling point. To rank items as equivalent, overlap them.
HCl, NaCl, N2, H2O
Chemistry
1 answer:
Trava [24]4 years ago
8 0

Answer: NaCl>HCl&H2O> N2

Explanation:

NaCl, as an ionic substance has a very high boiling point as expected. However, the boiling points of HCl and H2O depend on the relative concentration of the HCl and water, at 20% HCl, it boils at almost the same temperature as water due to extensive intermolecular hydrogen bonding. N2 comprises only of Vanderwaals forces hence it has the least boiling point.

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Given that a for HBrO is 2. 8×10^−9 at 25°C. What is the value of b for BrO− at 25°C?
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If Ka for HBrO is 2. 8×10^−9 at 25°C, then the value of Kb for BrO− at 25°C is 3.5× 10^(-6).

<h3>What is base dissociation constant? </h3>

The base dissociation constant (Kb) is defined as the measurement of the ions which base can dissociate or dissolve in the aqueous solution. The greater the value of base dissociation constant greater will be its basicity an strength.

The dissociation reaction of hydrogen cyanide can be given as

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Given,

The value of Ka for HCN is 2.8× 10^(-9)

The correlation between base dissociation constant and acid dissociation constant is

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Substituting values of Ka and Kw,

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Thus, we find that if Ka for HBrO is 2. 8×10^−9 at 25°C, then the value of Kb for BrO− at 25°C is 3.5× 10^(-6).

DISCLAIMER: The above question have mistake. The correct question is given as

Question:

Given that Ka for HBrO is 2. 8×10^−9 at 25°C. What is the value of Kb for BrO− at 25°C?

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