Answer:
The least number of forces required to stretch a spring is one.
Explanation:
Let suppose that spring is ideal, that is, that effects from its mass can be neglected since it is insignificant in comparison with external forces. In addition, let the spring have a linear behavior, meaning that net external longitudinal force exerted on spring is directly proportional to defomation. (Hooke's Law) That is:
(1)
(2)
Where:
- Net external force, measured in newtons.
- Spring constant, measured in newtons per meter.
- Deformation of spring, measured in meters.
Hence, the least number of forces required to stretch a spring is one.
Answer: Potential energy is energy stored in an object due to its position or arrangement. Kinetic energy is the energy of an object due to its movement its motion. Potential energy can be converted into kinetic energy, and kinetic energy can be converted into potential energy.
Answer:
s=800 m
Explanation:
Given that,
Acceleration of a runner, a = 4 m/s²
Time, t = 20 seconds
We need to find the distance covered by her. Initially, she was at rest. It means its initial velocity is equal to 0. So, using second equation of motion as follows :
Herre, u = 0
So, she will cover a distance of 800 m.
Answer:
solved
Explanation:
From the FBD in the attachment we can write that
N+ 80 sin37°= mg
N= 46×g-80×sin37=498.94 N
also, ma= 80×cos37°
a= 80×cos37°/46= 1.3889 m/s^2
also, 10m = 0.5at^2
put a= 1.3889 m/s^2
t= 2.095 secs
d) the speed v =at
v= 1.3889*2.095= 2.91 m/s^2
Answer:
772.65 years.
Explanation:
Semi major axis = R = 84 AU = 1.257 × 10¹³ m
According to the 3rd law of Kepler, T² = 4 π² R³ / GM
Here R is the semi major axis. G = 6.67 × 10⁻¹¹ SI units.
M is the mass of the Sun = 1.98 x 10³⁰ kg
T² = 4 (3.14)³ (1.257 × 10¹³ )³÷ (6.67 × 10⁻¹¹)(1.98 x 10³⁰)
⇒ Time period = T = 2.44 x 10¹⁰ seconds
1 s = 3.17 × 10⁻⁸ years
Converting the seconds to years, T = 772.65 years.