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maw [93]
2 years ago
14

Please help me answer the following question!

Physics
1 answer:
Troyanec [42]2 years ago
3 0

Answer:

P = 0

Explanation:

Momentum is defined as the quentity of motion contained in a body. Mathematically, it can be defined as the product of mass and velocity. So, in order to determine the Volkswagen Beetle, at rest, we can use the simple formula, as follows:

where,

P = Momentum of Volkswagen Beetle = ?

m = Mass of Volkswagen Beetle = 750 kg

v = Velocity of Volkswagen Beetle = 0 m/s (since, it is at rest)

Therefore,

P =

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Suppose the coefficient of static friction between a quarter and the back wall of a rocket car is 0.383. At what minimum rate wo
djverab [1.8K]

Answer:

25.59 m/s²

Explanation:

Using the formula for  the force of static friction:

f_s = \mu_s N --- (1)

where;

f_s = static friction force

\mu_s = coefficient of static friction

N = normal force

Also, recall that:

F = mass × acceleration

Similarly, N = mg

here, due to min. acceleration of the car;

N = ma_{min}

From equation (1)

f_s = \mu_s ma_{min}

However, there is a need to balance the frictional force by using the force due to the car's acceleration between the quarter and the wall of the rocket.

Thus,

F = f_s

mg = \mu_s ma_{min}

a_{min} = \dfrac{mg }{ \mu_s m}

a_{min} = \dfrac{g }{ \mu_s }

where;

\mu_s = 0.383 and g = 9.8 m/s²

a_{min} = \dfrac{9.8 \ m/s^2 }{0.383 }

\mathbf{a_{min}= 25.59 \ m/s^2}

3 0
2 years ago
1) Freddy drives 4 miles east to his friend's house. He then travels 9 more miles east to the supermarket. Finally on his way ba
timurjin [86]

Answer:

<h3>B. 19miles</h3>

Explanation:

If Freddy drives 4 miles east to his friend's house. He then travels 9 more miles east to the supermarket. Finally on his way back home he out  of gas 6 miles after leaving the supermarket, the distance travel by fred will be the sup of all the distances he covered throughout the journey.

Distance covered by fred = 4miles + 9miles + 6miles

Distance covered by fred = 13miles + 6miles

Distance covered by fred  = 19miles

8 0
3 years ago
An object is dropped from rest from the top of a 400 m cliff on Earth. If air resistance is negligible, what is the distance the
IrinaVladis [17]

Answer:

176.58 m

Explanation:

t = Time taken = 6 seconds

u = Initial velocity = 0

v = Final velocity

s = Displacement

g = Acceleration due to gravity = 9.81 m/s² = a

Equation of motion

s=ut+\dfrac{1}{2}at^2\\\Rightarrow s=0\times t+\dfrac{1}{2}\times 9.81\times 6^2\\\Rightarrow s=176.58\ m

The object travels 176.58 m from the cliff in 6 seconds.

8 0
3 years ago
What phenomenon will take place as a light wave bends when it passes from one medium into another?
Licemer1 [7]
Refraction
the fact or phenomenon of light, radio waves, etc. being deflected in passing obliquely through the interface between one medium and another or through a medium of varying density.
3 0
3 years ago
Read 2 more answers
The voltage ???? in a simple electrical circuit is slowly decreasing as the battery wears out. The resistance ???? is slowly inc
zimovet [89]

Answer:

The change in current at  R =456 \Omega is  \frac{dI}{dt}  = 7.032 * 10^{-5} A/s

Explanation:

From the question we are told that

    The resistance is R = 465 \Omega

     The current is  I = 0.09A

    The change in voltage with respect to time is \frac{dV}{dt}  = - 0.03 V/s

     The change in resistance with time is  \frac{dR}{dt}  =  0.03 \Omega /s

According to ohm's law

        V =  IR

differentiating with respect to time using chain rule

             \frac{dV}{dt}  =  I \frac{dR}{dt} + R * \frac{dI}{dt}

substituting value  at R = 456

             -0.0327 =  0.09 * 0.03 + 456* \frac{dI}{dt}

              \frac{dI}{dt}  = 7.032 * 10^{-5} A/s

6 0
3 years ago
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