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2 years ago

Which statements best describe the second stage of cellular respiration? Check all that apply.

Physics

2 answers:

grandymaker [24]2 years ago

7 0

Answer:

oxygen combines with small molecules. energy is released and it happens in the cytoplasm

Explanation:

Cerrena [4.2K]2 years ago

6 0

Answer:

B,C,D are the correct answers i just did it one edge for the unit review.

Explanation:

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The answer is letter C

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3 years ago

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In this problem, you will practice applying this formula to several situations involving angular acceleration. In all of these s

riadik2000 [5.3K]

Answer:

Part a)

$\alpha = \frac{2(m_1 - m_2)g}{(m_1 + m_2)L}$

Part b)

$\alpha = \frac{6(m1 - m_2)g}{3(m_1 + m_2)L + m_{bar}L}$

Explanation:

As we know that the see saw bar is massless so here torque due to two masses is given as

$\tau = I\alpha$

here we will have

$\tau = (m_1g - m_2g)(\frac{L}{2})$

now we will have inertia of two masses given as

$I = (m_1 + m_2)(\frac{L}{2})^2$

now we have

$I = (m_1 + m_2)\frac{L^2}{4}$

now the angular acceleration is given as

$\alpha = \frac{\tau}{I}$

so we have

$\alpha = \frac{2(m_1 - m_2)g}{(m_1 + m_2)L}$

Part b)

Now if the rod is not massles then we will have total inertia given as

$I = (m_1 + m_2)(\frac{L}{2})^2 + \frac{m_{bar}L^2}{12}$

so we will have

$I = (m_1 + m_2)\frac{L^2}{4} + \frac{m_{bar}L^2}{12}$

now the acceleration is given as

$\alpha = \frac{\tau}{I}$

$\alpha = \frac{6(m1 - m_2)g}{3(m_1 + m_2)L + m_{bar}L}$

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3 years ago

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Answer:

Explanation:

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2 years ago

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Answer:

An “international employee” is defined as an employee of Stanford University whose work site is located.

Explanation:

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3 years ago

Describe what happens to the KE of the simple pendulum as it swings back and forth.

diamong [38]

Answer:

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2 years ago

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