Answer:
.....what type of question is this
Explanation:
In the test, it is observed that water that is not too deep If carbon dioxide levels are not low enough, blackout causes elevation.
<h3>What is research?</h3>
Unique and methodical activity performed to improve the reservoir of knowledge is known as the research. . A research project might be a continuation of previous work in the topic.
By the following way, the test is conducted;
1. The effect of the conversation test on exercise intensity prescription and monitoring in competitive athletes. The sound of your breath might assist you figure out what's wrong.
Athletes require oxygen to give energy and to eliminate carbon dioxide, which is a waste product produced when energy is produced.Because it is a reliable indicator of ventilatory efficiency in cardiac patients.
Ventilatory threshold performance is used to determine the lactate threshold. The maximal rate of oxygen consumption recorded during activity is 5.VO2 max. It is higher in trained people than in unskilled people.
Hence,in the test it is observed that water that is not too deep If carbon dioxide levels are not low enough, blackout causes elevation.
To learn more about the research, refer to the link;
brainly.com/question/18723483
#SPJ1
You have to figure it out
Answer:
a) m =1 θ = sin⁻¹ λ / d, m = 2 θ = sin⁻¹ ( λ / 2d)
, c) m = 3
Explanation:
a) In the interference phenomenon the maxima are given by the expression
d sin θ = m λ
the maximum for m = 1 is at the angle
θ = sin⁻¹ λ / d
the second maximum m = 2
θ = sin⁻¹ ( λ / 2d)
the third maximum m = 3
θ = sin⁻¹ ( λ / 3d)
the fourth maximum m = 4
θ = sin⁻¹ ( λ / 4d)
b) If we take into account the effect of diffraction, the intensity of the maximums is modulated by the envelope of the diffraction of each slit.
I = I₀ cos² (Ф) (sin x / x)²
Ф = π d sin θ /λ
x = pi a sin θ /λ
where a is the width of the slits
with the values of part a are introduced in the expression and we can calculate intensity of each maximum
c) The interference phenomenon gives us maximums of equal intensity and is modulated by the diffraction phenomenon that presents a minimum, when the interference reaches this minimum and is no longer present
maximum interference d sin θ = m λ
first diffraction minimum a sin θ = λ
we divide the two expressions
d / a = m
In our case
3a / a = m
m = 3
order three is no longer visible
The speed of a mechanical wave depends on the mechanical properties
of the medium through which the wave is traveling.
The speed of an electromagnetic wave depends on the electrical properties
of the medium through which the wave is traveling.
It's pretty well unanimous for choice <em>A</em> .
