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emmainna [20.7K]
3 years ago
14

What is the most effective way to protect dry lands from desertification

Physics
2 answers:
liberstina [14]3 years ago
5 0

Answer:

The correct answer is Planting a tree belt (C)

Explanation:

I just got it right on my test:)

Sonja [21]3 years ago
4 0

Answer: Planting a tree belt.

Explanation:

The most effective method by which the desertification of the soil can be controlled is by planting more and more trees.

The process of desertification occurs when there is a loss of vegetation, water bodies and animals  from a particular area. Loss of trees makes the area look like desert.

So, planting trees along with some irrigation will help to cope with problem.

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A caterpillar crawls 20 feet in 5 minutes. What is the caterpillars crawling speed?
Pavel [41]
The equation is
s= d/t

In this case you would have to write it out as:
s= 20/5
Speed = 4
6 0
3 years ago
Which system of government has a leader that takes power by force
kvv77 [185]

Answer:

The Autocratic system of governance

Explanation:

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5 0
2 years ago
Read 2 more answers
A student is holding a stone at a certain height. The stone has 50 joules of potential energy and 0 joules of kinetic energy. Th
Hitman42 [59]

Answer:

d) The stone will have about 50 joules of kinetic energy and 0 joules of potential energy​ .

Explanation:

Given :

Initial Potential energy , P_i=50\ J .

Initial Kinetic energy , K_i=0\ J . ( because ball is in rest )

Now , we know , kinetic energy is maximum when an object reaches ground .

Also , potential energy is zero when an object is in ground .

We know , by conservation of energy :

Initial total energy = Final total energy

P_i+K_i=P_f+K_f\\\\50+0=0+K_f\\\\K_f=50 \ J

Therefore , option d) is correct .

6 0
3 years ago
Please answer this question​
FinnZ [79.3K]

Answer:

The circuits that were made previously were large and bulky, consisting of circuit components like resistor, capacitor, inductor, transistor, diodes, etc., which were connected with copper wires.

Explanation:

I am in confusion with mono electronic circuit and I am not want to made u confused person.

I am really sorry brother.

:-befrank

4 0
2 years ago
A diffusion couple, made by welding a thin onecentimeter square slab of pure metal A to a similar slab of pure metal B, was give
bezimeni [28]

Answer:

The value  is    H  =  18*10^{2} \  Atom / sec

Explanation:

From the question we are told that

  The atom fraction of metal A at point G is A  =  0.30 \ m

   The atom fraction of metal  A at a distance 5000nm from G is  A_2 = 0.35

   The number of atoms per m^3 is    N_h =  9 * 10^{28}

    The diffusion coefficient is  D =   2* 10^{-14 } m^2/s

Generally of the concentration of atoms of metal A at G is  

       N_A = A * N_h

=>    N_A =  0.3  * 9 * 10^{28}

=>     N_A =   2.7 * 10^{28} 2.7 atoms/m^3

Generally of the concentration of atoms of metal A at a distance 5000nm from G is  

       D =  0.35 *9 * 10^{28}

=>     D =  3.15 * 10^{28} \  atoms / m^3

The concentration gradient is mathematically represented as

   \frac{dN_A}{dx}  =  \frac{(3.15 - 2.7) * 10^{28} }{5000nm - 0 }

=> \frac{dN_A}{dx}  =  \frac{(3.15 - 2.7) * 10^{28} }{[5000 *10^{-9}] - 0 }  

=>   \frac{dN_A}{dx}  = 9 * 10^{20} / m^4  

Generally the flux of the atoms per unit  area according to Fick's Law  is mathematically represented as

       J =  -D* \frac{d N_A}{dx}

=>    J =  -2* 10^{-14 * 9 * 10^{20}

=>    J =  18*10^{6}\   atoms\ crossing\ /m^2 s

Generally if the cross-section area is a  =  1 cm^2 =  10^{-4} \  m^2

Generally the number of atom crossing the above area  per second is mathematically is  

      H  =  18*10^{6}    *  10^{-4}

=>    H  =  18*10^{2} \  Atom / sec

7 0
3 years ago
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