All categories

3 years ago

What is the most effective way to protect dry lands from desertification

Physics

2 answers:

liberstina [14]3 years ago

5 0

Answer:

The correct answer is Planting a tree belt (C)

Explanation:

I just got it right on my test:)

Sonja [21]3 years ago

4 0

Answer: Planting a tree belt.

Explanation:

The most effective method by which the desertification of the soil can be controlled is by planting more and more trees.

The process of desertification occurs when there is a loss of vegetation, water bodies and animals from a particular area. Loss of trees makes the area look like desert.

So, planting trees along with some irrigation will help to cope with problem.

You might be interested in

Stairway must have uniform riser height and tread depth; variations in riser height or tread depth shall not be over _______ inc

alexandr1967 [171]

Answer:

$\frac{3}{8} inches$

Explanation:

the variations in riser height or tread depth should not be grater than $\frac{3}{8} inches$ that is equal to 9.5 mm but the maximum riser height should be the $\frac{81}{4} inch$ but variation in riser height should not exceed to $\frac{3}{8} inches$ . The minimum riser height should be 7 inches which is equal to the 178 mm

5 0

3 years ago

Which element can form straight chains, branched chains, and rings

Mice21 [21]

Carbon atoms can form straight, and branched chains, and rings

6 0

3 years ago

Read 2 more answers

You are standing on a street corner with your friend. You then travel 14.0 m due west across the street and into your apartment

Margarita [4]

Answer:

Explanation:

We shall express each displacement vectorially , i for each unit displacement towards east , j for northward displacement and k for vertical displacement .

14 m due west = - 14 i

22.0 m upward in the elevator = 22 k

12 m north = 12 j

6.00 m east = 6 i

Total displacement = - 14 i + 22 k + 12 j + 6 i

D = - 8 i + 12 j + 22 k

magnitude = √ ( 8² + 12² + 22² )

= √ ( 64 + 144 + 484 )

= √ 692

= 26.3 m

Net displacement from starting point = 26.3 m .

5 0

2 years ago

What must be the magnitude of a uniform electric field if it is to have the same energy density as that possessed by a 0.50 T ma

Sindrei [870]

Answer:

E = 1.50 × $10^{8}$ V/m

Explanation:

given data

B = 0.50 T

solution

we know that energy density by the magnetic field is express as

$\mu _b = \frac{B}{2\mu _o}$ ...............1

and

energy density due to electric filed is

$\mu _e = \frac{\epsilon _o E^2}{2}$ ...............2

and here $\mu _b = \mu _ e$

so that

E = $\frac{B}{\sqrt{\mu _o \times \epsilon _o}}$ ...................3

put here value and we get

$E = \frac{0.50}{\sqrt{4\pi \times 10^{-7} \times 8.852 \times 10^{-12}}}$

E = 3 × $10^{8}$ × 0.50

E = 1.50 × $10^{8}$ V/m

6 0

2 years ago

the jet plane travels along the vertical parabolic path. when it is at point a it has speed of 200 m/s, which is increasing at t

givi [52]

Explanation:

Here is the complete question i guess. The jet plane travels along the vertical parabolic path defined by y = 0.4x². when it is at point A it has speed of 200 m/s, which is increasing at the rate .8 m/s^2. Determine the magnitude of acceleration of the plane when it is at point A.

→ The tangential component of acceleration is rate of increase in the speed of plane so,

$a_{t} = v = 0.8 m/s^{2}$