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klemol [59]
3 years ago
8

PLS HELP 20 POINTS

Chemistry
1 answer:
mixas84 [53]3 years ago
6 0
The answer is the third one because the animal died before the rock was there
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What is the last element in the periodic table?
borishaifa [10]

Answer:

Ununoctium

Explanation:

It's at the very end of the periodic table

6 0
3 years ago
Read 2 more answers
CHEM HELP ASAP!! <br><br> What mass of H2 would be needed to produce 208 kg of methanol?
Eddi Din [679]

So if we use the equation:

CO+2H_{2} → CH_{3}OH

We can then determine the amount of H_{2} needed to produce 208 kg of methanol.

So let's find out how many moles of methanol 208 kg is:

Methanol molar weight = 32.041g/mol

So then we can solve for moles of methanol:

208kg*\frac{1,000g}{1kg} *\frac{1mol}{32.041g} =6,491.68mol

So now that we have the amount of moles produced, we can use the molar ratio (from the balanced equation) of hydrogen and methanol. This ratio is 2:1 hydrogen:methanol.

Therefore, we can set up a proportion to solve for the moles of hydrogen needed:

\frac{2}{1} =\frac{x}{6,491.68}

x=12,983.36mol

So now that we have the number of moles of H_{2} that are produced, we can then use the molar weight of hydrogen to solve for the mass that is needed:

12,983.36mol*\frac{2.016g}{1mol} =26,174.45g_H_{2}

Therefore, the amount of diatomic hydrogen (H_{2}) that is needed to produce 208kg of methanol is 2.62x10^{4}g.

3 0
3 years ago
43 milliliters of water weighs 43 g. what is the density of the water?
Anastaziya [24]

Answer:

\rho =1g/mL

Explanation:

Hello,

In this case, since the density is defined as the ratio between the mass and the volume as shown below:

\rho =\frac{m}{V}

We can compute the density of water for the given 43 g that occupy the volume of 43 mL:

\rho =\frac{43g}{43mL}=1g/mL

Regards.

4 0
4 years ago
Which of the following provides an instantaneous measure of radioactivity:
Nikitich [7]

Answer:

Option 2 is correct.

Scintillation counters and Geiger Counters provide instantaneous measure of radioactivity.

Explanation:

Of the three means of measuring radioactivity presented. Only Film-badge dosimeter lacks a sensitive photo-detector piece that instantaneously converts the amount of radiation seen into electrical waves. It collects the radiation over time and the film is then developed after a particular point in time for the radioactivity collected to be measured.

Although used majorly for gamma rays and neutrons, the scintillation counters uses a scintillator to convert ionizing radiation (like the two mentioned at the start of this passage), into photons that the photo-detector (usually very sensitive) converts into electrical signals for immediate reading. It gives the energy and intensity of the radiation intended to.be measured.

The Geiger Muller counter, the most used measure of radioactivity across all fields, uses the tube (which contains inert gases) as the sensitive radiation detecting piece. High voltage maintained in the tube makes the gases conductive and it transmits the intemsity of radiation to the processing part of the counter which converts this reading to electrical signals, immediately for reading. Unlike the scintillation counters, it doesn't measure the energy of the radiation.

Hope this Helps!!!

5 0
4 years ago
Read 2 more answers
how many grams of CsXeF7 can be produced from the reaction of 15.2 grams of CsF and 260 grams of XeF6?
Sveta_85 [38]

Answer:

39.72 g

Explanation:

Given data:

Mass of CsF = 15.2 g

Mass of XeF₆ = 260 g

Mass of Cs[XeF₇] = ?

Solution:

Chemical reaction:

CsF + XeF₆   →  Cs[XeF₇]

Number of moles of CsF:

Number of moles = mass/ molar mass

Number of moles = 15.2 g/151.9 g/mol

Number of moles = 0.1 mol

Number of moles of XeF₆ :

Number of moles = mass/ molar mass

Number of moles = 260 g/245.28 g/mol

Number of moles = 1.06 mol

Now we will compare the moles of Cs[XeF₇] with both reactants.

                            CsF               :            Cs[XeF₇]

                               1                 :                 1

                             0.1                :              0.1

                             XeF₆            :           Cs[XeF₇]

                                 1               :               1

                                1.06           ;              1.06

Number of moles of Cs[XeF₇] produce by  CsF are less so it will limiting reactant and limit the yield of Cs[XeF₇].

Mass of Cs[XeF₇]:

Mass = number of moles × molar mass

Mass = 0.1 mol × 397.2 g/mol

Mass = 39.72 g

4 0
4 years ago
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