C. rate = k[C4H9Br]
The slow step is always the rate-determining step. In the slow step, C4H9Br is the only reactant and has a coefficient of 1, so it is first order in the rate law.
Answer:
6.11 J/g°C
Explanation:
We need to use the heat equation: q = mCΔT, where q is the amount of heat required in Joules, m is the mass in grams, C is the heat capacity, and ΔT is the change in temperature.
Here, we know q = 23,200 Joules, m = 28 grams, and the ΔT is just the difference of the temperatures: 150 - 14.4 = 135.6°C. Substitute these values to find C:
q = mCΔT
23,200 = 28 * C * 135.6
C = 6.11
Thus, the specific heat is 6.11 J/g°C.
Answer:
Lets the total pressure is Pt and the individual gases are designated as pH2, pCO2, pNe, pO2.
Pt = pCO2+ pNe+pO2+ pH2
285KPa = 13 KPa+ 14 KPa + 157 KPa +pH2
Now add the partial pressure of CO2, Ne and O2 which is equal to 184 KPa.
285 KPa = 184 KPa + pH2
Now subtract the individual pressure of each gas from thje total pressure.
285 KPa - 184 KPa = pH2
101 KPa = pH2
The partial pressure of hydrogen is 101 KPa.
Answer:
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Explanation:
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Answer:
see explanation
Explanation:
the pheny acetate, is an ester in an aromatic ring. We have the bencene and in one of the carbon, it's the acetate ion.
Now, the acetate has two oxygens with at least one pair of electrons that are available to do resonance in all the structure of the aromatic ring, because the aromatic ring has double bonds all over the ring, and can have resonance with the electrons of the oxygens.
This resonance structure can be in all the ring, or just in some positions of the ring. In this case the ortho position, which is the carbon 2. So we only can have two or three resonance structure. See the picture below for resonance.
