The mass of the sample reported is 3.5465 g option e is correct.
Mass is the quantitative measure of the physical body.
The mass of the empty sample container is given as 12 g.
The mass of empty as well as sample containers is given as 15.5465 g.
Therefore, the mass of the sample will be given as :
Mass of sample = mass of a sample as well as empty containers - a mass of empty sample container
= 15.5465 - 12
= 3.5465 g
Therefore, the mass of the sample reported is 3.5465 g option e is correct.
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Complete question:
Your question is incomplete, but most probably your full question was, A label on an empty sample container reads 12.00 g. you add in a sample of a compound and the mass of the sample container obtaining 15.5465 g. what should the mass of the sample be reported as?
a) 3.546 g
b) 3.54 g
c) 4 g
d) 4.0 g
e) 3.5465 g
Answer:
its true hope this helped :)
Given that the volume and amount of water are kept constant,
P/T = constant
P₁/T₁ = P₂/T₂
Normal atmospheric pressure is 746 mmHg and normal boiling point of water is 100 °C.
746/100 = 589/T₂
T₂ = 79.0 °C
Answer:
Explanation:
The chemical reaction involved is as follows
H₃BO₃ + 4HF = HBF₄ + 3H₂O
1 mol 1 mol
mol weight of H₃BO₃ is 61.84 gm
50g = 50 / 61.84 mol.
= 0.8 mol.
.8 mol of H₃BO₃ will form .8 mol of BF₄⁻ ion .
Answer:
Lithium oxide, Li₂O.
Explanation:
Hello!
In this case, according to the given amounts, it is possible to write down the chemical reaction as shown below:
Which means that the metallic oxide has the following formula: M₂O. Next, we can set up the following proportional factors according to the chemical reaction:
Thus, we perform the operations in order to obtain:
So we solve for x as shown below:
Whose molar mass corresponds to lithium, and therefore, the metallic oxide is lithium oxide, Li₂O.
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