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Lubov Fominskaja [6]
3 years ago
13

What volume of water should be added to 4.6 g of KCl to make 4m solution

Chemistry
1 answer:
dusya [7]3 years ago
8 0

Answer:

Explanation:

We want 4M, or 4 moles/liter.  4.6g of KCl is (4.0g KCl/74.55g/mole KCl) = 0.0617 moles of KCl.

Write the definition of Molar and set the volume to X ( X will tell us how many liters are needed to make a 4M solution from 0.0617 moles of KCl)

4.0M = (0.0617 moles KCl)/X

(4.0 moles/liter)*X = 0.0617 moles KCl

X = (0.0617 moles KCl)/(4.0 moles KCl)

X = 0.0154 liters, or 15.4 ml

===

[(0.0154 liters)*(4.0 moles/liter) = 0.0617 moles KCl]

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2) The partial pressure of N₂ gas in the larger container = 0.206 atm.

3) The total pressure in the vessel = 0.321 atm.

Explanation:

  • To calculate the partial pressure of each gas, we can use the general law of ideal gas: PV = nRT.

where, P is the partial pressure of the gas in atm,

V is the volume of the vessel in L,

n is the no. of moles of the gas,

R is the general gas constant (R = 0.082 L.atm/mol.K),

T is the temperature of the gas in K.

<u><em>1) What is the partial pressure of SO₂ gas in the larger container?</em></u>

<em>∵ P = nRT/V.</em>

n = mass/molar mass = (3.0 g)/(64.066 g/mol) = 0.047 mol.

R = 0.082 L.atm/mol.K.

T = 26 °C + 273.15 = 299.15 K.

V = 10.0 L. (The volume of the new container)

∴ P = nRT/V = (0.047 mol)(0.082 L.atm/mol.K)(299.15 K)/(10.0 L) = 0.115 atm.

<u><em>2) What is the partial pressure of N₂ gas in the larger container?</em></u>

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n = mass/molar mass = (2.35 g)/(28.0 g/mol) = 0.084 mol.

R = 0.082 L.atm/mol.K.

T = 26 °C + 273.15 = 299.15 K.

V = 10.0 L. (The volume of the new container)

∴ P = nRT/V = (0.084 mol)(0.082 L.atm/mol.K)(299.15 K)/(10.0 L) = 0.206 atm.

<u><em>3) What is the total pressure in the vessel?</em></u>

  • According to Dalton's law the total pressure exerted is equal to the sum of the partial pressures of the individual gases.

<em>∵ The total pressure in the vessel = the partial pressure of SO₂ + the partial pressure of N₂.</em>

∴ The total pressure in the vessel = 0.115 + 0.206 = 0.321 atm.

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