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solmaris [256]
2 years ago
9

There are 9 children and 13 adults on a bus.

Mathematics
2 answers:
Brut [27]2 years ago
7 0

Answer:

22:9

Step-by-step explanation:

I took the test

In-s [12.5K]2 years ago
3 0

Answer:

22 to 9

Step-by-step explanation:

13+9=22

add the 22 and keep the nine the same

and it would look like this 22 to 9 or 9 to 22

<h2>BRAINIEST?</h2>
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Toko follows a budget to buy supplies to paint his room. He spends 1/2 of his budget on a roller, a tray, and tape. He spends $1
Natasha_Volkova [10]
The answer is $36.

B - budget
So the calculation is as following:
B= \frac{1}{2}B + 12.27 +  \frac{3.82}{ \frac{2}{3} } = \frac{1}{2}B + 12.27 + \frac{3.82*3}{2}=   \frac{1}{2}B + 12.27 +5.73
B= \frac{1}{2} B + 18
B- \frac{1}{2}B = 18
\frac{1}{2}B = 18
B = 18*2=36
3 0
3 years ago
PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
vodomira [7]

12x^2-75=3(4x^2-25)=3(2^2x^2-5^2)=3((2x)^2-5^2)=3(2x+5)(2x-5)\\\\\text{Used:}\ a^2-b^2=(a+b)(a-b)\\\\Answer:\ 5

8 0
3 years ago
A child's toy is in the shape of a cone on top of a
sammy [17]

Answer:

1. 167.55

2. 10.77

Step-by-step explanation:

For #1 use the formula for volume of cone: V=\pi r^2\frac{h}{3}, and for #2 use the Pythagorean Theorem: a^2+b^2=c^2

7 0
3 years ago
Assume the readings on thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. Find the pro
lisov135 [29]

Answer:

0.0326 = 3.26% probability that a randomly selected thermometer reads between −2.23 and −1.69.

The sketch is drawn at the end.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 0°C and a standard deviation of 1.00°C.

This means that \mu = 0, \sigma = 1

Find the probability that a randomly selected thermometer reads between −2.23 and −1.69

This is the p-value of Z when X = -1.69 subtracted by the p-value of Z when X = -2.23.

X = -1.69

Z = \frac{X - \mu}{\sigma}

Z = \frac{-1.69 - 0}{1}

Z = -1.69

Z = -1.69 has a p-value of 0.0455

X = -2.23

Z = \frac{X - \mu}{\sigma}

Z = \frac{-2.23 - 0}{1}

Z = -2.23

Z = -2.23 has a p-value of 0.0129

0.0455 - 0.0129 = 0.0326

0.0326 = 3.26% probability that a randomly selected thermometer reads between −2.23 and −1.69.

Sketch:

3 0
3 years ago
Simplify.<br><br> 4n + 12 + 7n
QveST [7]
11n+12- combined like terms
5 0
4 years ago
Read 2 more answers
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