![\bf \textit{volume of a cone}\\\\ V=\cfrac{\pi r^2 h}{3}~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ r=23.9\\ h=100 \end{cases}\implies V=\cfrac{\pi (23.9)^2(100)}{3} \\\\\\ V=\cfrac{57121\pi }{3}\implies V\approx 59816.97\implies \stackrel{\textit{rounded up}}{V=59817} \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bvolume%20of%20a%20cone%7D%5C%5C%5C%5C%20V%3D%5Ccfrac%7B%5Cpi%20r%5E2%20h%7D%7B3%7D~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%20h%3Dheight%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20r%3D23.9%5C%5C%20h%3D100%20%5Cend%7Bcases%7D%5Cimplies%20V%3D%5Ccfrac%7B%5Cpi%20%2823.9%29%5E2%28100%29%7D%7B3%7D%20%5C%5C%5C%5C%5C%5C%20V%3D%5Ccfrac%7B57121%5Cpi%20%7D%7B3%7D%5Cimplies%20V%5Capprox%2059816.97%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Brounded%20up%7D%7D%7BV%3D59817%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)
now, for the second one, we know the diameter is 10, thus its radius is half that or 5.
![\bf \textit{volume of a cone}\\\\ V=\cfrac{\pi r^2 h}{3}~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ r=5\\ V=225 \end{cases}\implies 225=\cfrac{\pi (5)^2 h}{3}\implies 225=\cfrac{25\pi h}{3} \\\\\\ \cfrac{225}{25\pi }=\cfrac{h}{3}\implies \cfrac{9}{\pi }=\cfrac{h}{3}\implies \cfrac{27}{\pi }=h\implies 8.59\approx h\implies \stackrel{\textit{rounded up}}{8.6=h}](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bvolume%20of%20a%20cone%7D%5C%5C%5C%5C%20V%3D%5Ccfrac%7B%5Cpi%20r%5E2%20h%7D%7B3%7D~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%20h%3Dheight%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20r%3D5%5C%5C%20V%3D225%20%5Cend%7Bcases%7D%5Cimplies%20225%3D%5Ccfrac%7B%5Cpi%20%285%29%5E2%20h%7D%7B3%7D%5Cimplies%20225%3D%5Ccfrac%7B25%5Cpi%20h%7D%7B3%7D%20%5C%5C%5C%5C%5C%5C%20%5Ccfrac%7B225%7D%7B25%5Cpi%20%7D%3D%5Ccfrac%7Bh%7D%7B3%7D%5Cimplies%20%5Ccfrac%7B9%7D%7B%5Cpi%20%7D%3D%5Ccfrac%7Bh%7D%7B3%7D%5Cimplies%20%5Ccfrac%7B27%7D%7B%5Cpi%20%7D%3Dh%5Cimplies%208.59%5Capprox%20h%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Brounded%20up%7D%7D%7B8.6%3Dh%7D)
It takes 3 years its plotted on the graph on the x axis .
Answer:
The answer to your question is: y = -2/3 x + 18
Step-by-step explanation:
Data
Point = (-9, 12)
line y = 3/2x -1/2 perpendicular
Process
The line must be perpendicular to the line given. Then,
slope is the line given = 3/2, we change it because the lines must be perpendicular ,
New slope M = -2/3
New line y-y1 = m(x - x1)
y - 12 = -2/3 (x + 9) Substitution
3( y - 12) = -2(x + 9)
3y - 36 = -2x - 18 Simplify
3y = -2x - 18 + 36
3y = -2x + 18
y = -2/3 x+ 18 Result
Answer:
1. 4 and 4sqrt2
2. 6sqrt2 and 6sqrt2
3. 5 and 5sqrt2
4. 5sqrt2 and 5sqrt2
5. 6 and 6
6. 8 and 8sqrt2
7. sqrt3 and sqrt6
8. sqrt2 and sqrt4
Step-by-step explanation:
Answer:
All we do is do 3.5 x 5 to get 17.5 water!
Step-by-step explanation:
