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2 years ago

If a golf ball and a ping-pong ball both move with the same kinetic energy, which has the greater speed?.

1 answer:

3 0

Given what we know, if a golf ball and a ping-pong ball both move with the same kinetic energy, the ping-pong ball must be traveling at a greater speed.

<h3>How do we know that the ping-pong ball is faster?</h3>

This has to do with the formula for kinetic energy.
The formula is $KE= 1/2 *m * v^2$ .
This means that mass and velocity are proportional.
If the total Kinetic energies are equal, the object with the lower mass must have a higher velocity.
Since ping-pong balls are known to have very little mass, we know it must be traveling faster.

Therefore, we can confirm that if a golf ball and a ping-pong ball both move with the same kinetic energy, the ping-pong ball must be traveling at a greater speed due to its lower mass and the relationship between mass and speed when calculating kinetic energy.

To learn more about kinetic energy visit:

brainly.com/question/999862?referrer=searchResults

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3 years ago

URGENT!!!!!!!<br><br> PLEASE HELP WITH THIS PHYSICS PROBLEM

Levart [38]

Explanation:

Let

$x_1$ = distance traveled while accelerating

$x_2$ = distance traveled while decelerating

The distance traveled while accelerating is given by

$x_1 = v_0t + \frac{1}{2}at^2 = \frac{1}{2}at^2$

$\:\:\:\:\:= \frac{1}{2}(2.5\:\text{m/s}^2)(30\:\text{s})^2$

$\:\:\:\:\:= 1125\:\text{m}$

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$v = at = (2.5\:\text{m/s}^2)(30\:\text{s}) = 75\:\text{m/s}$

This will be the initial velocity when start calculating for the distance it traveled while decelerating.

$v^2 = v_0^2 + 2ax_2$

$0 = (75\:\text{m/s})^2 + 2(-0.65\:\text{m/s}^2)x_2$

Solving for $x_2,$ we get

$x_2 = \dfrac{(75\:\text{m/s})^2}{2(0.65\:\text{m/s}^2)}$

$\:\:\:\:\:= 4327\:\text{m}$

Therefore, the total distance x is

$x = x_1 + x_2 = 1125\:\text{m} + 4327\:\text{m}$

$\:\:\:\:= 5452\:\text{m}$

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