Question

The hydraulic lift in a car repair shop has an output diameter of 30 cm and is to lift cars up to 2000 kg. determine the fluid gage pressure that must be maintained in the reservoir.

Answer 1

Answer:

$P = 2.77 \times 10^5 Pa$

Explanation:

As we know that pressure is defined as the ratio of normal force and area

here we know that

normal force is due to weight of the car

$F = mg$

$F = (2000)(9.8)$

$F = 19600 N$

now the area is given as

$A = \pi r^2$

$A = \pi(0.15)^2$

$A = 0.0707 m^2$

Now the pressure is given as

$P = \frac{19600}{0.0707}$

$P = 2.77 \times 10^5 Pa$

Answer 2

Given Data: Diameter 'd' = 30 cm = 0.3 m Lifting Weight 'W' = mg = 2000*9.81 N = 19,620 N Calculations: Area of the lift 'A' = pi\over4*d^2=pi\over4*0.3^2=0.07 m^2

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