Answer:
Distance = 64 metres
Displacement = 28 metres
Direction = northward
Explanation:
Given that a kayaker moves 22 meters northward, then 18 meters southward , and finally 24 meters northward
Distance covered is only about the magnitude of the length covered.
Distance = 22 + 18 + 24 = 64 metres
The direction will be considered when calculating the displacement
Let northward be positive and southward be negative
Displacement = 22 - 18 + 24 = 28 metres
Since the displacement is positive, the direction of the motion is northward.
Answer:
Explanation:
From the given information:
Let the first weight be
= 80 kg
The weight of the buddy be
= 120 kg
The weight of Bubba be
= 60 kg
Also, since you and Budda are a distance of 4m to each other, then the length to which both meet buddy will be:

The length of the boat be
= 4 m
∴
We can find the center of mass of the system by using the formula:

Correct question is;
A thermal tap used in a certain apparatus consists of a silica rod which fits tightly inside an aluminium tube whose internal diameter is 8mm at 0°C.When the temperature is raised ,the fits is no longer exact. Calculate what change in temperature is necessary to produce a channel whose cross-sectional is equal to that of the tube of 1mm. (linear expansivity of silica = 8 × 10^(-6) /K and linear expansivity of aluminium = 26 × 10^(-6) /K).
Answer:
ΔT = 268.67K
Explanation:
We are given;
d1 = 8mm
d2 = 1mm
At standard temperature and pressure conditions, the temperature is 273K.
Thus; Initial temperature; T1 = 273K,
Using the combined gas law, we have;
P1×V1/T1 = P2×V2/T2
The pressure is constant and so P1 = P2. They will cancel out in the combined gas law to give:
V1/T1 = V2/T2
Now, volume of the tube is given by the formula;V = Area × height = Ah
Thus;
V1 = (πd1²/4)h
V2 = (π(d2)²/4)h
Thus;
(πd1²/4)h/T1 = (π(d2)²/4)h/T2
π, h and 4 will cancel out to give;
d1²/T1 = (d2)²/T2
T2 = ((d2)² × T1)/d1²
T2 = (1² × T1)/8²
T2 = 273/64
T2 = 4.23K
Therefore, Change in temperature is; ΔT = T2 - T1
ΔT = 273 - 4.23
ΔT = 268.67K
Thus, the temperature decreased to 268.67K
Answer:
F = 50636.873 N
Explanation:
given,
bucket of water = 700-kg
length of cable = 20 m
Speed = 40 m/s
angle of the cable = 38.0°
let air resistance be = F
tension in rope be = T
T cos 38° = m×g..................(1)
..........(2)
equation (1)/(2)


F = 50636.873 N
Hence the force exerted on the bucket is equal to F = 50636.873 N
I believe it is C i am not sure