Answer:
The correct answer to the following question is that there are 5 horses, 1 pig and 94 rabbits.
Explanation:
Given information -
Horses cost = $10
Pigs = $3
Rabbits = $.50
There are total of 100 animals, which are bought for $100 in total.
So by using simple equations we can solve this problem,
where let number of horses be x
number of pigs be y
number of rabbits be z
so the first equation that we can make by using given information is -
x + y + z = 100 (total of 100 animals bought ) _ _ equation 1
10 x + 3 y + .5 z = $100 _ _ equation 2
Now multiplying equation 2 by 2 and then subtract that from equation 1
(10 x + 3 y + .5 z = $100) x 2
= 20 x + 6 y + z = $200 _ _ equation 3
Now subtracting equation 3 from 1 -
20 x + 6 y + z = $200
-
x + y + z = 100
19 x + 5 y = 100
Here 19 x and 5 y have to be a multiple of 5 ( where x and y are integers ), therefore the only possible value of x here can be 5 and if the value of x =5 , then the value of y will be equal to 1,
19 x 5 + 5 x 1 = 100
Now putting the value of x and y in equation 2,
10 x 5 + 3 x 1 + .5 x z = $100
50 + 3 + .5 z = 100
.5 z = 47 ( 100 - 53 )
z = 47 / .5
z = 94
