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Alex_Xolod [135]
3 years ago
12

Compare and contrast electrical and magnetic forces

Physics
1 answer:
erik [133]3 years ago
3 0

Answer:

the eletrical forces are created when an object is both moving charges and stationary charges.

the magnetic forces are created when an act on only moving charges.

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A piano wire with mass 2.95 g and length 79.0 cm is stretched with a tension of 29.0 N . A wave with frequency 105 Hz and amplit
Romashka-Z-Leto [24]

The concept needed to solve this problem is average power dissipated by a wave on a string. This expression ca be defined as

P = \frac{1}{2} \mu \omega^2 A^2 v

Here,

\mu = Linear mass density of the string

\omega =  Angular frequency of the wave on the string

A = Amplitude of the wave

v = Speed of the wave

At the same time each of this terms have its own definition, i.e,

v = \sqrt{\frac{T}{\mu}} \rightarrow Here T is the Period

For the linear mass density we have that

\mu = \frac{m}{l}

And the angular frequency can be written as

\omega = 2\pi f

Replacing this terms and the first equation we have that

P = \frac{1}{2} (\frac{m}{l})(2\pi f)^2 A^2(\sqrt{\frac{T}{\mu}})

P = \frac{1}{2} (\frac{m}{l})(2\pi f)^2 A^2 (\sqrt{\frac{T}{m/l}})

P = 2\pi^2 f^2A^2(\sqrt{T(m/l)})

PART A ) Replacing our values here we have that

P = 2\pi^2 (105)^2(1.8*10^{-3})^2(\sqrt{(29.0)(2.95*10^{-3}/0.79)})

P = 0.2320W

PART B) The new amplitude A' that is half ot the wavelength of the wave is

A' = \frac{1.8*10^{-3}}{2}

A' = 0.9*10^{-3}

Replacing at the equation of power we have that

P = 2\pi^2 (105)^2(0.9*10^{-3})^2(\sqrt{(29.0)(2.95*10^{-3}/0.79)})

P = 0.058W

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An event, a person, a deed, or an object can have a long-lasting or momentary effect. How might you determine if the effect has
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I want to know about the inventions caused due to rain. Like the Benjamin Franklin's Lightning Conductor. I have to make a chart
nydimaria [60]
Franklin had been waiting for an opportunity like this. He wanted to demonstrate the electrical nature of lightning, and to do so, he needed a thunderstorm.

He had his materials at the ready: a simple kite made with a large silk handkerchief, a hemp string, and a silk string. He also had a house key, a Leyden jar (a device that could store an electrical charge for later use), and a sharp length of wire. His son William assisted him.

Franklin had originally planned to conduct the experiment atop a Philadelphia church spire, according to his contemporary, British scientist Joseph Priestley (who, incidentally, is credited with discovering oxygen), but he changed his plans when he realized he could achieve the same goal by using a kite.
3 0
3 years ago
(will give brainliest to whoever is first and gives reason) A mass is spun in a circle with a frequency of 40Hz. What is the per
Blizzard [7]

Answer:

\huge\boxed{T = 0.025\ seconds}

Explanation:

<u>Given:</u>

Frequency = f = 40 Hz

<u>Required:</u>

Time period = T = ?

<u>Formula:</u>

\sf T = 1 / f

<u>Solution:</u>

T = 1 / 40

T = 0.025 seconds

\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
4 0
3 years ago
An alpha particle collides with an oxygen nucleus, initially at rest. The alpha particle is scattered at an angle of 25.0° above
Greeley [361]

Answer:

v_{i}= 19\times 10^5\ m/s

Explanation:

given,

scattering angle of alpha particle = 25.0°  above its initial direction of motion

oxygen nucleus recoils at = 50.0° below this initial direction.

final speed of the oxygen = 2.08×10⁵ m/s

mass of alpha particle = 4.0 u

mass o oxygen nucleus = 16 u

momentum conservation along x- axis

m_{a}v_{i} = m_a v_a cos\theta + m_o v_o cos\theta

4v_{i} = 4\times v_a cos25^0 + 16\times 2.08 \times 10^5 cos50^0

v_{i}= \dfrac{3.625\times v_a+ 21.39\times 10^5}{4}....(1)

Along y-direction

0 = m_av_a sin \theta - m_ov_o sin\theta

0 = 4\times v_a sin 25 - 16\times  2.08 \times 10^5 sin50^0

v_a = \dfrac{25.49 \times 10^5}{1.69}

v_a = 15.082\times 10^5\ m/s

putting value in equation (1)

v_{i}= \dfrac{3.625\times 15.082\times 10^5+ 21.39\times 10^5}{4}

v_{i}= 19\times 10^5\ m/s

5 0
3 years ago
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