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Alenkasestr [34]
3 years ago
8

Describe the flow of energy from the Sun to producers and then to a consumers

Biology
2 answers:
lidiya [134]3 years ago
6 0
Well, the sun shoots it's powerful rays against the plants which is known as  photosynthesis, which makes plants grow then once the plant or tree produces it goods, it gets picked and off to the store it goes.. So the consumer can pick it up and eat it...
valina [46]3 years ago
4 0
Hi lol again,

The chlorophyll in a plants leaves absorbs light energy from the sun which is then later used to make glucose and oxygen. Consumers eat the plants to get nutrients. Consumers get their energy from the food they eat. 

Hoped I Helped
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En un cruce entre peces naranjas y peces grises se obtiene una generación (f1) de 50% peces grises . Realice el cruce y explique
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Answer:

Uno de los progenitores es heterocigoto para color naranja (Nn) y el otro parental es homocigoto recesivo para gris (nn). Al haber una cruza entre un homocigoto recesivo y un heterocigoto, la 50% de la progenie expresa color naranja (Nn), mientras que el otro 50% expresa color gris (nn).

Explanation:

<u>Datos disponibles:</u>

  • Cruce entre peces naranjas y peces grises
  • 50% de la F1 son peces grises
  • Naranja dominante sobre gris

Podemos nombrar el alelo dominante para color naranja <em>N</em>, y al alelo recesivo  para color gris <em>n</em>.

Para que en un cruce entre dos fenotipos distintos, el 50% de la primer camada exprese uno de estos fenotipos, entonces uno de los parentales debe ser heterocigoto, mientras que el otro parental debe ser homocigoto recesivo. De esta forma 50% de la primera generación expresara uno de los fenotipos, mientras que el otro 50% expresará el otro fenotipo.

Supongamos que uno de los parentales lleva el genotipo <em>Nn</em>, y el otro parental es <em>nn</em>.

Cruce:

Parental)      Nn    x     nn

Gametas)   N    n       n    n

Fenotipos) Naranja     Gris

Cuadro de Punnett)      N           n

                            n       Nn         nn

                            n       Nn         nn

F1)  2/4 = 1/2 = 50% de la progenie tendrá genotipo heterocigoto, Nn

     2/4 = 1/2 = 50% de la progenie tendrá genotipo homocigota recesivo,    

     nn

     50% de la progenie será color naranja (Nn)

     50% de la progenie será color gris (nn)

               

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