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Norma-Jean [14]
2 years ago
11

2. What are the innate defense systems?

Physics
1 answer:
Degger [83]2 years ago
7 0

Answer:

2)Innate, or nonspecific, immunity is the defense system with which you were born. It protects you against all antigens. Innate immunity involves barriers that keep harmful materials from entering your body. These barriers form the first line of defense in the immune response.

3)The first line of defence (or outside defence system) includes physical and chemical barriers that are always ready and prepared to defend the body from infection. These include your skin, tears, mucus, cilia, stomach acid, urine flow, 'friendly' bacteria and white blood cells called neutrophils.

4)The second line of defense is nonspecific resistance that destroys invaders in a generalized way without targeting specific individuals: Phagocytic cells ingest and destroy all microbes that pass into body tissues. For example macrophages are cells derived from monocytes (a type of white blood cell).

5)The adaptive defense consists of antibodies and lymphocytes, often called the humoral response and the cell mediated response. The term 'adaptive' refers to the differentiation of self from non-self, and the tailoring of the response to the particular foreign invader.

6)Innate immunity is comprised of different components including physical barriers (tight junctions in the skin, epithelial and mucous membrane surfaces, mucus itself); anatomical barriers; epithelial and phagocytic cell enzymes (i.e., lysozyme), phagocytes (i.e., neutrophils, monocytes, macrophages), inflammation- .

8)Types of phagocytes

In humans, and in vertebrates generally, the most-effective phagocytic cells are two kinds of white blood cells: the macrophages (large phagocytic cells) and the neutrophils (a type of granulocyte)

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A ship's propeller of diameter 3 m makes 10.6 revolutions in 30s. What is the angular velocity of the propeller?
ycow [4]

Answer:

The angular velocity of the propeller is 2.22 rad/s.

Explanation:

The angular velocity (ω) of the propeller is:  

\omega = \frac{\Delta \theta}{\Delta t}                              

Where:

θ: is the angular displacement = 10.6 revolutions

t: is the time = 30 s

\omega = \frac{\Delta \theta}{\Delta t} = \frac{10.6 rev*\frac{2\pi rad}{1 rev}}{30 s} = 2.22 rad/s

Therefore, the angular velocity of the propeller is 2.22 rad/s.

I hope it helps you!

5 0
3 years ago
A plane on the ground will weigh:
kenny6666 [7]

On ground weight of plane will be measured as its actual weight which will be given as

W = mg

now when plane is in air its weight is measured as combined effect of earth gravitational force and buoyancy force both

so weight in air will be given as

W_{air} = mg - F_b

here since net effect due to air is opposite to the direction of weight so in air the plane weight will be measure less than its weight on ground.

so answer will be

A)more than a plane in the air

3 0
3 years ago
Read 2 more answers
Please help answer #14!!!!!!!
jeka94

When a heavy football player and a light one run into each other, does the lighter player really exert as much force on the heavy player s the heavy player exerts on the light one. Yes. The interaction between the two players, the force each exerts on the other have equal strength.

Hope this helps you!!!

Please mark this as the brainliest one!!!

7 0
3 years ago
A charged particle is observed traveling in a circular path in a uniform magnetic field. If the particle had been traveling four
8090 [49]

Answer:

The new radius of the trajectory of the particle is four times the previous radius

Explanation:

In order to know what is the radius of the trajectory of the charged particle, if its speed is four times as fast, you take into account the following formula, which describes the radius of a charged particle in a magnetic field:

r=\frac{mv}{qB}          (1)

If the speed of the particle is for time as fast, that is, v' = 4v, you obtain, in the equation (1):

r'=\frac{mv'}{qB}=\frac{m(4v)}{qB}=4\frac{mv}{qB}=4r

The new radius of the trajectory of the particle is four times the previous radius

8 0
3 years ago
In an "atom smasher," two particles collide head on at relativistic speeds. If the velocity of the first particle is 0.741c to t
galina1969 [7]

Answer:

W_x = 0.9156\ c

Explanation:

given,

velocity of particle 1 = 0.741 c to left

velocity of second particle = 0.543 c to right

relative velocity between the particle = ?

for the relative velocity calculation we have formula

W_x = \dfrac{|u_x - v_x|}{1-\dfrac{u_xv_x}{c^2}}

u_x = 0.543 c

v_x = - 0.741 c

W_x = \dfrac{0.543 c - (-0.741 c)}{1-\dfrac{(0.543 c)(-0.741 c)}{c^2}}

W_x = \dfrac{0.543 c +0.741 c)}{1+\dfrac{(0.543)(0.741)c^2}{c^2}}

W_x = \dfrac{1.284c}{1+0.402363}

W_x = 0.9156\ c

Relative velocity of the particle is W_x = 0.9156\ c

5 0
3 years ago
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