Rate of speed, probs is the answer
This question is solved using an available similar problem as data provided for the forces was not given.
Repeat the same steps outlined for your problem.
Regards.
Answer:
F = 1.598 KN , Q = 90 degree (+ y-axis)
Explanation:
Sum of Forces in x-direction to the left (+)
2 cos (30) + 3cos (60) + F*cos (Q) = F_a ..... 1
Sum of Forces in y-direction to the up (+)
2 sin (30) + F*sin (Q) - 3 sin (60) ...... 2
Using Eq 2 and solve:
F*sin (Q) = 1.598 KN
F_min when sin (Q) is max, max possible value of sin(Q) = 1 @ Q = 90 degrees.
Hence,
F_min = 1.598 KN
Using Eq 1 @ Q = 90 degrees and F = 1.598 KN:
F_a = 2 cos (30) + 3cos (60) = 3.2 KN
Answer:
Explanation:
1.wrap bar magnet in a plastic baggie and remove the iron filings from the mixture by using a bar magnet. Place a small piece of scrap paper on the scale and “tare” the scale. Then place filings on the scrap paper and record (e) the mass of the iron filings. Don't throw out the iron–save it to be recollected.
2.When sand is added to water it either hangs in the water or forms a layer at the bottom of the container. Sand therefore does not dissolve in water and is insoluble. It is easy to separate sand and water by filtering the mixture. Salt can be separated from a solution through evaporation.
3.Sand (mostly silicon dioxide) is not.
Pour the salt and sand mixture into a pan.
Add water. ...
Heat the water until the salt dissolves. ...
Remove the pan from heat and allow it to cool until it's safe to handle.
Pour the salt water into a separate container.
Now collect the sand.
Pour the salt water back into the empty pan.
Heat the salt water until the water boils. Continue boiling it until the water is gone and you're left with the salt.
Another way you can separate the salt water and sand is to stir up the sand/salt water and pour it through a coffee filter to capture the sand.
I believe it's Seismographs, Tiltmeters, and Correlation Spectometers.
Hopefully I helped ^~^
