Between centre of curvature and principal focus.
If the transformer’s primary coil has 20 times as many turns of wire in it as the secondary coil has, then the secondary coil provides a small voltage rise for the large amount of current that flows through it.
Answer: Option B
<u>Explanation:</u>
A transformer has a two types of coils, the first one is primary coils and the second one is secondary coil. A secondary coils with hardly any turns in it provides the charges going through it just limited quantities of energy.
Without a long separation over which to do chip away at the charges streaming in the loop, the transformer delivers just a little ascent in the voltage of those charges. Be that as it may, the coil can give this little voltage to ascend to a huge current without requiring an excess of power supply from the input circuit.
Answer:
The force is 7.8 N.
Explanation:
Given that,
Mass of small object = 2M
Mass of large object = 4M
Here, M = 1.0 kg
Force of the small block = 5.2 N
We need to calculate the acceleration of 4 kg block
Using formula of force
The 2 kg block is also accelerating at 1.3 m/s², making a total of 6 kg.
We need to calculate the force
Using formula of force
Put the value into the formula
Hence, The force is 7.8 N.
Answer:
The initial current in the circuit is 0.1873 mA
Explanation:
Given;
capacitance is given as 3.67 x 10⁻⁶ F
resistance is given as 8010 Ω
voltage across the circuit is 1.5 V
Since the capacitor is initially uncharged, the capacitive reactance is zero.
From ohms law;
Voltage across the circuit is directly proportional to the opposition to the flow of current.
V = IR
I = V/R
I = 1.5/8010
I = 0.0001873 A = 0.1873 mA
Therefore, the initial current in the circuit is 0.1873 mA
