Answer:
The work done on the gas = 2PV
Explanation:
In this question, we need to apply the basic gas laws to determine the word done.
For this question, we need to draw a PV diagram (a pressure-volume diagram), which I have made and attached in the attachment. So please refer to that attachment. I will be using this diagram to solve for the work done on the gas.
So, Please refer to the attachment number 1. where x -axis is of volume and y-axis is of pressure.
As we know that, the work done on the gas is equal to the area under the curve.
W = Area of the triangle
W = 0.5 x ( base) x ( height)
W = 0.5 x (BC) x (AC)
W = 0.5 x (3V-V) x (3P-P)
W = 2PV
Hence, the work done on the gas = 2PV
Answer:
Pushes and pulls refer to the force that attracts or repels certain other materials without actually touching them.
Explanation:
Pushes and pulls are the forces exerted by the magnet on certain materials around it without, actually touching them. This push and pull is exerted through a region around the magnet called its magnetic field. The strength of this push and pull force is determined by, the strength of the magnetic field. A strong push or pull force is exerted by a strong magnetic field, and in turn a strong magnet and, a weak push and pull force is exerted by a weak magnetic field and, in turn a weak magnet. A push force is a repulsion while a pull force is an attraction. When a magnetic object is in the region of the magnetic field, it either attracts or is repelled away from the source of the magnetic field.
When the two spheres touch each other, part of the charge recombine together. The part of charge that recombines is the excess of positive charge on sphere Y,
, that recombines with an equivalent charge of
located on sphere X. As a result, the total charge remained on the two spheres is the excess of negative charge remained on sphere X:
Since the two spheres are identical, they have same capacity, so this charge will now redistribute equally on the two spheres: therefore, at the end, each sphere will have
Answer:
only you are in motion
Explanation:
it is because the ground causes friction to make you stop but you are the object in motion :)
M1V1 + M2V2 = M1V1' + M2V2'
where:
M1 is the mass of the large marble = 0.05 kg
V1 is the initial velocity of the large marble = 0.6 m/sec
M2 is the mass of the small marble = 0.03 kg
V2 is the initial velocity of the small marble = 0 m/sec (marble is at rest)
V1' is the final velocity of the large marble = -0.2 m/sec
V2' is the final velocity of the small marble that we want to calculate
Substitute with the givens in the above equation to get V2' as follows:
M1V1 + M2V2 = M1V1' + M2V2'
(0.05)(0.6) + (0.03)(0) = (0.05)(-0.2) + 0.03V2'
0.03 = -0.01 + 0.03V2'
0.03V2' = 0.03+0.01 = 0.04
V2' = 0.04/0.03
V2' = 1.334 m/sec
