Since there is no weight, I would assume that this is a 100g of pure compound.
Okay so I would be changing the percentage to gram to solve for the mole.
So
40.0g C (1 mol C/12.01 g C) = 3.33 mol C
6.73g H (1 mol H/1.01 g H ) = 6.66 mol H
53.3g O (1 mol O/16.00 g O) = 3.33 mol O
With that, two of our moles is 3.33, so we consider that are our 1, as it is also the lowest. Therefore the empirical formula is CH2O
D: is the anwser that your looking for
This equation represents a single replacement reaction. Single replacement reactions consist of one element reacting with one compound on the reactant side (left side of the equation) and they form one new element and one new compound on the product side of the equation (right side).
Answer:
The total number of orbitals for a given n value is n2.
Explanation:
For a hydrogen atom with n=1, the electron is in its ground state; if the electron is in the n=2 orbital, it is in an excited state.
Answer:
6CO2 + 6H20 + ENERGY = C6H12O6 + 6O2
Explanation:
Carbon dioxide + water + energy from light produces glucose and oxygen
