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vampirchik [111]
3 years ago
10

As a consequence of the discovery of the nucleus by rutherford, which model of the atom is thought to be true?

Chemistry
2 answers:
ivanzaharov [21]3 years ago
8 0
The correct answer is A.
8090 [49]3 years ago
7 0

Answer:

The correct answer is<em> a. electrons are distributed around the nucleus and occupy almost all the volume of the atom.</em>

Explanation:

Rutherford's experiment was to bombard a very thin sheet of gold (Au atoms) with alpha particles (positive charges). He thought that if the atom is composed by both negative and positive charges together (as Thompson had proposed) it would be electrically neutral and the positive charges would pass without deviation. He observed that most of the particles passed throught the sheet without deviation (as he expected) <u>but several particles suffered a considerable deviation and others had bounced towards the emission source</u>. So, he proposed a new atomic model in which the positive charge is concentred in the nucleus (alpha particles which passed nearly the nucleus were repelled with a considerable deviation) and surrounding the nucleus are the electrons (negative charge) which occupy a larger volume.

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If the rate of a reaction increases by a factor of 64 when the concentration of reactant increases by a factor of 4, what is the
igomit [66]

The reaction is of order three with respect to the reactant.

<h3>Explanation</h3>

The rate of a reaction of order n about a certain reactant is proportion to the concentration of that reactant raised to the n-th power. This is true only if  concentrations of any other reactants stay constant in the whole process.

In other words, Rate = constant × [Reactant]ⁿ, Rate ∝ [Reactant]ⁿ. (The symbol "∝" reads "proportional to".)

In this question,

[4 × Reactant]ⁿ ÷ [Reactant]ⁿ = 64.

In other words, 4ⁿ = 64, where n is the order of the reaction with respect to this reactant.

It might take some guesswork to find the value of n. Alternatively, n can be solved directly with a calculator using logarithms. Taking natural log of both sides:

\ln{4^n} = \ln{64}\\n\; \ln{4} = \ln{64}\\n = \frac{\ln{64}}{\ln{4}} = 3.

Evaluating \ln(64) / \ln(4) on Google or on a calculator with support for ln (the natural log) will give the value of n- no guesswork required.

n = 3. Therefore, the reaction is of order three with respect to this reactant.

3 0
3 years ago
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