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Svet_ta [14]
3 years ago
14

In the drawing, water flows from a wide section of a pipe to a narrow section. In which part of the pipe is the volume flow rate

the greatest?
Physics
1 answer:
guapka [62]3 years ago
7 0

Answer:

Volume flow rate is the same in both sections of the pipe

Explanation:

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zhuklara [117]
The answer for this question is acceleration
8 0
4 years ago
Read 2 more answers
Consider a double-slit with a distance between the slits of 0.04 mm and slit width of 0.01 mm. Suppose the screen is a distance
scZoUnD [109]

Answer:

The distance between the places where the intensity is zero due to the double slit effect is 15 mm.

Explanation:

Given that,

Distance between the slits = 0.04 mm

Width = 0.01 mm

Distance between the slits and screen = 1 m

Wavelength = 600 nm

We need to calculate the distance between the places where the intensity is zero due to the double slit effect

For constructive fringe

First minima from center

x_{1}=\dfrac{\lambda D}{2d}

Second minima from center

x_{2}=\dfrac{3\lambda D}{2d}

The distance between the places where the intensity is zero due to the double slit effect

\Delta x_{d}=x_{2}-x_{1}

\Delta x_{d}=\dfrac{3\lambda D}{2d}-\dfrac{\lambda D}{2d}

\Delta x_{d}=\dfrac{\lambda D}{d}

Put the value into the formula

\Delta x_{d}=\dfrac{600\times10^{-9}\times1}{0.04\times10^{-3}}

\Delta x_{d}=0.015 =15\times10^{-3}\ m

\Delta x_{d}=15\ mm

Hence, The distance between the places where the intensity is zero due to the double slit effect is 15 mm.

8 0
3 years ago
The area vector of a square loop of 5 turns of a conductor each with side length of 0.2 m carrying a current of 2 A is antiparal
Anon25 [30]

Answer:

M= 0.4 Am^2

Explanation:

From the question we are told that:

Number of turns  N=5N=5

Conductor each with side length L=0.2m

Current I=2A

Magnetic field  B=50.0T

Generally the equation for the total magnetic moment  M is mathematically given by

M = current * area

M= I * A

M = 2 * (5* 0.2*0.2)  

M = 2 * 0.2

M= 0.4 Am^2

3 0
3 years ago
The amplitude, or magnitude, of a sinusoidal source is the maximum value of the source. What is the amplitude of the voltage sou
liraira [26]

Answer:

<em>A = 0.05 V</em>

Explanation:

<u>Sinusoidal Functions</u>

A sinusoid or sinusoidal function is a sine or cosine which general equation is

F(x)=A.sin(wt-\phi)

Or also

F(x)=A.cos(wt-\phi)

Where A is the amplitude or maximum value, w is the angular frequency, t is the time and \phi is the phase shift.

Comparing the given expression with the general formula

v(t)=50cos(2000t-45^o) mV

We can establish that A=50 mV = 0.05 V

A = 0.05\ V

7 0
4 years ago
Why were quasars and active galaxies not initially recognized as being “special” in some way?
djyliett [7]

Answer:

In the past, astronomers look into the sky and the universe as a whole with an idea that it is a place where stars are born, transition through their life stages and ultimately die and this is because they couldnt differentiate between stars, quasars and active galaxies because with advanced equipment, they all look similar but as they technological ages arrived, they were able see that they are not the same.

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