(a) The acceleration of the ball while it is in flight has a magnitude of 9.81 m/s2 in downward direction.
(b) The velocity of the ball when it reaches its maximum height is zero.
(c) The initial velocity of the ball is 17.36 m/s.
(d) The maximum height it reaches is 15.36 m.
<h3>
Acceleration of the ball</h3>
The acceleration of the ball while it is in flight has a magnitude of 9.81 m/s2 in downward direction.
<h3>Velocity of the ball at maximum height</h3>
The velocity of the ball decreases as the ball moves upwards and eventually becomes zero at maximum height.
<h3>Initial velocity of the ball</h3>
v = u - gt
at maximum height, final velocity, v = 0
0 = u - gt
u = gt
u = 9.81 x 1.77
u = 17.36 m/s
<h3>Maximum height reached by the projectile</h3>
h = ut - ¹/₂gt
h = 17.36(1.77) - ¹/₂(9.81)(1.77²)
h = 15.36 m
Thus, the acceleration of the ball while it is in flight has a magnitude of 9.81 m/s2 in downward direction.
The velocity of the ball when it reaches its maximum height is zero.
The initial velocity of the ball is 17.36 m/s.
The maximum height it reaches is 15.36 m.
Learn more about maximum height here: brainly.com/question/12446886
#SPJ1
