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Svetlanka [38]
2 years ago
11

A tennis player tosses a tennis ball straight up and then catches it after 1.77 s at the same height as the point of release.

Physics
1 answer:
Alex_Xolod [135]2 years ago
3 0

(a) The  acceleration of the ball while it is in flight has a magnitude of 9.81 m/s2 in downward direction.

(b) The velocity of the ball when it reaches its maximum height is zero.

(c) The initial velocity of the ball is 17.36 m/s.

(d) The maximum height it reaches is 15.36 m.

<h3>Acceleration of the ball</h3>

The acceleration of the ball while it is in flight has a magnitude of 9.81 m/s2 in downward direction.

<h3>Velocity of the ball at maximum height</h3>

The velocity of the ball decreases as the ball moves upwards and eventually becomes zero at maximum height.

<h3>Initial velocity of the ball</h3>

v = u - gt

at maximum height, final velocity, v = 0

0 = u - gt

u = gt

u = 9.81 x 1.77

u = 17.36 m/s

<h3>Maximum height reached by the projectile</h3>

h = ut - ¹/₂gt

h = 17.36(1.77) - ¹/₂(9.81)(1.77²)

h = 15.36 m

Thus, the  acceleration of the ball while it is in flight has a magnitude of 9.81 m/s2 in downward direction.

The velocity of the ball when it reaches its maximum height is zero.

The initial velocity of the ball is 17.36 m/s.

The maximum height it reaches is 15.36 m.

Learn more about maximum height here: brainly.com/question/12446886

#SPJ1

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Answer:

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Explanation:

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Y = \frac{FL}{A\Delta L}

F = \frac{ YA\Delta L}{L}

= \frac{2.0*10^{11}*25*10^{-4}8.58*10^{-3}}{27}

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The frequency of the green light is 6x10^{14}Hz

Explanation:

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Green light is part of the visible region. Therefore, the frequency can be determined by the following equation:

c = \lambda \cdot \nu  (1)

Where c is the speed of light, \lambda is the wavelength and \nu is the frequency.  

Notice that since it is electromagnetic radiation, equation 1 can be used. Remember that light propagates in the form of an electromagnetic wave (that is a magnetic field perpendicular to an electric field).

Then, \nu can be isolated from equation 1

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