(x - h)^2 = 4p(y - k)
(-1 - 3)^2 = 4p(8 - 0.5)
(-4)^2 = 4p(7.5)
16 = 30p
p = 16/30
p = 8/15
(x - 3)^2 = 16/15(y - 0.5)
15(x^2 - 6x + 9) = 16y - 8
15x^2 - 90x + 135 = 16y - 8
16y = 15x^2 - 90x + 135 + 8
y = 15/16 x^2 - 90/16 x + 143/16
f(x) = 15/16 x^2 - 90/16x + 143/16
This is a horizontal line at y = -3. If you want to find it mathematically, you could find the slope (y2-y1)/(x2-x1) and you would get 0 over 5, so you know the slope is zero. Pick either point and substitute the numbers into point-slope formula. I went with (3, -3) and got (y - -3) = 0(x-3). The right side is just 0, and if you subtract three from both sides to isolate y, you get the equation y = -3.
Answer:
ok
Step-by-step explanation:
Simple.....
always remember the y-intercept is where your line hits the y-axis... or where it hits the vertical axis...
As we can see this line hits the y-axis at (0,3)-->> y-intercept=3
Thus, your answer.
Answer:
Step-by-step explanation:
hg(x) means you multiply h(x) times g(x) and then we will set it equal to 
.
hg(x) = 
which simplifies to
. Now set that equal to :
and get everything on the same side and factor:
. Factor by grouping:
and factor out what's common in each set of ( ):
which factors out to
. But 
factors somoe to:
(x + 1)(x - 1)(x - 1) = 0 So the solutions for this are
x = -1, 1
