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satela [25.4K]
2 years ago
7

At the beginning of year 1, Sam invests $700 at an annual compound interest

Mathematics
1 answer:
Aleksandr-060686 [28]2 years ago
6 0

at the beginning of year 4, only 3 years have elapsed, the 4th year hasn't started yet, since it's at the beginning, so at the beginning of year 4 we can say only 4-1 years have elapsed.

~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$700\\ r=rate\to 5\%\to \frac{5}{100}\dotfill &0.05\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=\textit{elapsed years}\dotfill &3 \end{cases}

A=700\left( 1 + \frac{0.05}{1} \right)^{1\cdot 3}\implies A = 700(1+0.05)^3\implies A(4)=700(1+0.05)^{4-1} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill A(n)=700(1+0.05)^{n-1}~\hfill

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Answer:

The population mean of at least one treatment effect are different.

Step-by-step explanation:

An analysis of variance (ANOVA) is conducted in order to determine if there are significant differences between the values of the population mean with respect to the response variable for the domains that under the effects of different treatments. A low p-value leads to reject the null hypothesis of the following hypothesis system:

H_0: \mu_1=\mu_2=...=\mu_k\\\\\\H_a: \mu_i \neq\mu_j, for $ for some i, j between 1 and k.$

Rejecting H0 means that this hypothesis is false and, in turn, allows us to conclude that the population mean of one of the domains is different from the others.

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3 years ago
BRAINLIEST Another submarine's descent can be represented as y = -240x, where y is the elevation and x is time in hours. How lon
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Step-by-step explanation:

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2 years ago
Which graph represents the function f (x) = StartFraction 2 x minus 1 Over x minus 1 EndFraction?
Lubov Fominskaja [6]

The correct description of the graph:

<em>"One curve opens up and to the right in quadrant 1, and the other curve down and to the left in </em><em>quadrants </em><em>2, 1, and 4."</em>

<h3>Which graph is the graph of the given functions?</h3>

Here we have the function:

f(x) = \frac{2x - 1}{x - 1}

The graph of this function can be seen below:

Then we can see that a curve opens up on quadrant 1, and down on quadrants 2 and 3 (it pass throw quadrant 1 for a little bit).

Then the correct option is:

<em>"One curve opens up and to the right in </em><em>quadrant </em><em>1, and the other curve down and to the left in </em><em>quadrants </em><em>2, 1, and 4."</em>

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If you want to learn more about rational functions:

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What is the constant proportionality in the equation 3 y=2x
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2

Step-by-step explanation:

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3 years ago
Hello, I am currently very stuck with this problem and I am unsure as to how I would solve it.
borishaifa [10]

We have the equation

20y=x^2-10-15

Let's complete the square, to do it let's add and subtract 25 on the right side

\begin{gathered} 20y=x^2-10-15+25-25 \\  \\ 20y=(x-5)^2-15-25_{} \\  \\ 20y=(x-5)^2-40 \\  \\  \end{gathered}

Now we can have y in function of x

\begin{gathered} y=\frac{1}{20}(x-5)^2-2 \\  \\  \end{gathered}

Now we can already identify the vertex because it's in the vertex form:

y=a(x-h)+k

Where the vertex is

(h,k)

As we can see, h = 5 and k = -2, then the vertex is

(5,-2)

Now we can continue and find the focus, the focus is

\mleft(h,k+\frac{1}{4a}\mright)

We have a = 1/20, therefore

\begin{gathered} \mleft(5,-2+5\mright) \\  \\ (5,3) \end{gathered}

The focus is

(5,3)

And the last one, the directrix, it's

y=k-\frac{1}{4a}

Then

\begin{gathered} y=-2-5 \\  \\ y=-7 \end{gathered}

Hence the correct answer is: vertex (5, -2); focus (5, 3); directrix y = -7

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1 year ago
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