Answer:
A. 2Fe + 3Cl2 --> 2FeCl3
B. 2Fe + 3O2 --> 2Fe2O3
C. C4H10O + 4O2 --> 4CO2 + 5H2O
D. C7H16 + 11O2 --> 7CO2 + 8H2O
Explanation:
The rule that we will use to solve this problem is:
M2*V1 = M2*V2 where:
M1 is the initial concentration = 3.5 m
V1 is the initial volume = 0.25 l = 250 ml
M2 is the final concentration = 9 m
V2 is the final volume that we need to find
Substitute with the givens in the above equation to get V2 as follows:
3.5*250 = 9*V2
V2 = 97.2223 ml
Answer:
34.6 cm³
Explanation:
<em>A chemistry student needs 55.0 g of carbon tetrachloride for an experiment. By consulting the CRC Handbook of Chemistry and Physics, the student discovers that the density of carbon tetrachloride is 1.59 g/cm³. Calculate the volume of carbon tetrachloride the student should pour out. Be sure your answer has the correct number of significant digits.</em>
Step 1: Given data
- Mass of carbon tetrachloride (m): 55.0 g
- Density of carbon tetrachloride (ρ): 1.59 g/cm³
Step 2: Calculate the required volume of carbon tetrachloride
Density is an intrinsic property of matter. It can be calculated as the quotient between the mass of the sample and its volume.
ρ = m/V
V = m/ρ
V = 55.0 g/(1.59 g/cm³)
V = 34.6 cm³
The chemistry student should pour 34.6 cm³ of carbon tetrachloride.
Answer:
prepared by mixing 20 ml of 0050 m hcl with 30 ml of 010 m ba oh 2 ... No. of milliequivalents of HCl = 2× 0.05 × 1. =1.
Explanation:
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