1 3/4 Ounces or 1.75 Ounces!
Basically 21/12 = 1.75!
(Mark me as the brainliest if this helps!)
Answer:
The reaction can produce 287 grams of iron(II) carbonate
Explanation:
To solve this question we must find the moles of iron(II) chloride that react. Using the chemical equation we can find the moles of iron(II) carbonate and its mass -Molar mass FeCO3: 115.854g/mol-
<em>Moles FeCl2:</em>
1.24L * (2.00mol / L) = 2.48 moles FeCl2
As 1 mol FeCl2 produce 1 mol FeCO3, the moles of FeCO3 = 2.48 moles
<em>Mass FeCO3:</em>
2.48mol * (115.854g / mol) =
<h3>The reaction can produce 287 grams of iron(II) carbonate</h3>
Answer:
TRUE
Explanation:
The total length of the wires will affect the amount of resistance. The longer the wire, the more resistance that there will be.
Iron (II) oxide FeO Fe : O = 1 : 1
Iron (III) oxide Fe₂O₃ Fe : O = 2 : 3
