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2 years ago

Two parallel lines are cut by a transversal, as shown below. Solve for b. Then explain your reasoning.

Mathematics

2 answers:

AleksandrR [38]2 years ago

5 0

Answer:

b=14

Step-by-step explanation:

the two labeled angles are vertical angles. according to the vertical angles theorem, they must be equivalent. therefore, we can set them equal to each other and solve.

5b=b+56

4b=56

b=14

GarryVolchara [31]2 years ago

3 0

5b=b+56
4b=56
b=14
The two angles are congruent by vertical angles. Set them equal and solve for b.

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Answer:

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Step-by-step explanation:

step 1

Find the $sin(\theta)$

we have

$csc(\theta)=\frac{3}{2}$

Remember that

$csc(\theta)=\frac{1}{sin(\theta)}$

therefore

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step 2

Find the $cos(\theta)$

we know that

$sin^{2}(\theta) +cos^{2}(\theta)=1$

we have

$sin(\theta)=\frac{2}{3}$

substitute

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$cos^{2}(\theta)=\frac{5}{9}$

square root both sides

$cos(\theta)=\pm\frac{\sqrt{5}}{3}$

we have that

$cos(\theta) < 0$ ---> given problem

$cos(\theta)=-\frac{\sqrt{5}}{3}$

step 3

Find the $tan(\theta)$

we know that

$tan(\theta)=\frac{sin(\theta)}{cos(\theta)}$

we have

$sin(\theta)=\frac{2}{3}$

$cos(\theta)=-\frac{\sqrt{5}}{3}$

substitute

$tan(\theta)=\frac{2}{3}:-\frac{\sqrt{5}}{3}=-\frac{2}{\sqrt{5}}$

Simplify

$tan(\theta)=-\frac{2\sqrt{5}}{5}$

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