Hi Pupil Here's Your answer :::
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The resulting direction of motion of the various forces will be depending upon the which force is greater. The greater force will puch the rest all other forces and will definitely move the object to the direction of the greater force .
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Hope this helps
Answer:
60.6 m
Explanation:
For vertical displacement of 80 m , initial velocity downwards u = 0
h = ut + 1/2 g t²
80 = 0 + 1/2 x 9.8 x t²
t = 4.04 s
During this period , rock will be displaced horizontally with uniform velocity .
horizontal displacement = 15 x 4.04 = 60.6 m .
Given parameters:
Mass given = 1kg
Unknown:
Weight of the body at pole and equator = ?
Solution:
Both locations are on the surface of the earth. Generally, we take 9.8m/s² as the acceleration due to gravity on the earth.
Weight = mass x acceleration due to gravity
But little disparity occurs in the value of acceleration due to gravity from the pole to equator. This is due to equatorial bulge.
At the equator , 9.780 m/s²
pole 9.832 m/s²
Weight at equator = 1 x 9.780 = 9.78N
Weight at the pole = 1 x 9.832 = 9.832N
Answer:
v = 17.15 m/s
Explanation:
given,
angle of ramp = 17.0°
length of ramp(l) = 30 m
height of the ramp =
h = 15 m
using energy of conservation
v = 17.15 m/s
speed of block reaching at the bottom = v = 17.15 m/s
Answer:
Explanation:
A ) Distance between two adjacent anti-node will be equal to distance between two adjacent nodes . So the required distance is 15 cm .
B ) wave-length, amplitude, and speed of the two traveling waves that form this pattern are as follows
wave length = same as wave length of wave pattern formed. so it is 30 cm
amplitude = 1/2 the amplitude of wave pattern formed so it is .850 / 2 = .425 cm
Speed = frequency x wavelength ( frequency = 1 / time period )
= 1 / .075) x 30 cm
400 cm / m
C ) maximum speed
= ω A
= (2π / T) x A
= 2 X 3.14 x .85 / .075 cm / s
= 71.17 cm / s
minimum speed is zero.
D ) The shortest distance along the string between a node and an antinode
= Wavelength / 4
= 30 / 4
= 7.5 cm