Answer:
The price of
1 adult ticket = $15
1 student ticket = $9
Step-by-step explanation:
Let
The price of adult tickets be represented by a
The price of student tickets be represented by s
Therefore:
On the first day of ticket sales the school sold 4 adult tickets and 10 student tickets for a total of $150.
4a + 10s = $150.... Equation 1
The school took in $105 on the second day by selling 1 adult ticket and 10 student tickets.
a + 10s = $105.... Equation 2
a = $105 - 10s
Therefore, we substitute : $105 - 10s = a in Equation 1
4a + 10s = $150.... Equation 1
4($105 - 10s) + 10s = $150
$420 - 40s + 10s = $150
Collect like terms
- 40s + 10s = $150 - $420
-30s = -$270
Divide both sides by -30
-30s/-30 = -$270/-30
s = $9
We find a
a = $105 - 10s
a = $105 - 10($9)
a = $105 - $90
a = $15
Therefore, the price of
1 adult ticket = $15
1 student ticket = $9
Answer:
m<0
Step-by-step explanation:
-5/3>m- 5/3+ 2/4m
Simplify both sides of the inequality.
-5/3>5/3m+-5/3
Flip the equation
5/3m+-5/3< -5/3
Add 5/3 to both sides
5/3m + -5/3 +5/3< -5/3 + 5/3
5/3m<0
Multiplying both sides by 3/5
(3/5)×(5/3m)<(3/5)×(0)
m<0
Answer:
240
Step-by-step explanation:
(2x36)/2=36
(36+39)x2/2=75
(31+39)x2/2=70
(14+31)x2/2=45
(2x14)/2=14
14+45+70+75+36=240
Answer:
If
Step-by-step explanation:
Given
Required
Solve
First, we change / to *
Apply difference of two squares
Factorize:
x - 3 cancels out:
y - 5 cancels out
Take L.C.M
Open brackets
Collect Like Terms
Factorize:
Hence:
If