Answer:
(A) The force would be lower on the school day than the weekend.
Explanation:
In a school day the bus is on the road travelling with kids. But in a weekend it is parked. When a object stays still that means the the force which is working on the earth by the bus is equal to the force which works on the bus by the earth. we can understand it clearly by, Newton's second law of motion.
This pertains to the behavior of objects for which all existing forces are not balanced. The second law states that the acceleration of an object is dependent upon two variables - the net force acting upon the object and the mass of the object. so as it is when it is balanced it is not moving.
And on a school day the bus is moving so it has a force pulling itself forward . so it means that the force which the bus has is greater than the gravitational force.
Answer:
dt/dx = -0.373702
dt/dy = -1.121107
Explanation:
Given data
T(x, y) = 54/(7 + x² + y²)
to find out
rate of change of temperature with respect to distance
solution
we know function
T(x, y) = 54 /( 7 + x² + y²)
so derivative it x and y direction i.e
dt/dx = -54× 2x / (7 +x² + y²)² .........................1
dt/dy = -54× 2y / (7 + x² + y²)² .........................2
now put the value point (1,3) as x = 1 and y = 3 in equation 1 and 2
dt/dx = -54× 2(1) / (7 +(1)² + (3)²)²
dt/dx = -0.373702
and
dt/dy = -54× 2(3) / (7 + (1)² + (3)²)²
dt/dy = -1.121107
Answer:
Answer is option b) 2.97m
Explanation:
With the relationship between the force exerted by the runner and the mass that it has, I can determine the acceleration it will have:
F= m × a ⇒ a= (650 kg ×(m/s^2)) / (70kg)= 9.286 (m/s^2)
With the acceleration that prints the force exerted and the time I can determine the distance traveled in the interval:
Distance= (1/2) × a × t^2 = (1/2) × 9.286 (m/s^2) × ((0.8s)^2)= 2.97m
When you lay down your weight is distributed over a much larger surface area than while standing. You are putting a much greater force on a much smaller area standing.
