1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Lerok [7]
3 years ago
15

Which list correctly describes the usual order of planets inward toward the sun?

Physics
1 answer:
Sati [7]3 years ago
7 0

Option B

Neptune, Uranus, Saturn, Jupiter, Mars, Earth, Venus, Mercury correctly describes the usual order of planets inward toward the sun

<u>Explanation:</u>

Our solar system continues much considerably than the eight planets that revolve around the Sun. The position of the planets in the solar system, commencing inward to the sun is the accompanying: Neptune, Uranus, Saturn, Jupiter, Mars, Earth, Venus, Mercury.

Most next to the Sun, simply rocky material could resist the heat. For this logic, the first four planets: Mercury, Venus, Earth, and Mars are terrestrial planets.  The four large outer worlds — Jupiter, Saturn, Uranus, and Neptune: because of their enormous size corresponding to the terrestrial planets. They're also frequently composed of gases like hydrogen, helium, and ammonia preferably than of rocky surfaces.

You might be interested in
Use the f=ma formula to determine your weight in newtons AND pounds on the Moon and Pluto you have a mass of 70.3 kilograms
Julli [10]

Answer:

rrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrr

Explanation:rrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrr

6 0
3 years ago
An electron in an atom's orbital shell, labeled X in the model below, released enough energy to move to a different orbital shel
Delicious77 [7]

Answer:

Lower energy shell which will be nearer to the nucleus.

Explanation:

When electron move from one energy level to another, an electron must gain or lose just the right amount of energy.

When atoms releases energy, electrons move into lower energy levels.  The electrons in the shells aways from the nucleus have more energy as compared to the electrons in the nearer shells.

Electrons with the lowest energy are found closest to the nucleus, where the attractive force of the positively charged nucleus is the greatest. Electrons that have higher energy are found further away

7 0
3 years ago
Coherent light with wavelength 598 nm passes through two very narrow slits, and the interference pattern is observed on a screen
Stella [2.4K]

Answer:

1.196 μm

Explanation:

D = Screen distance = 3 m

\lambda = Wavelength = 598 m

y = Distance of first-order bright fringe from the center of the central bright fringe = 4.84 mm

d = Slit distance

tan\theta=\frac{y}{D}\\\Rightarrow \theta=tan^{-1}{\frac{y}{D}}\\\Rightarrow \theta=tan^{-1}{\frac{4.84\times 10^{-3}}{3}}\\\Rightarrow \theta=0.09243\ ^{\circ}

sin\theta=\frac{\lambda}{d}\\\Rightarrow d=\frac{\lambda}{sin\theta}\\\Rightarrow d=\frac{598\times 10^{-9}}{sin0.09243}\\\Rightarrow d=0.00037066\ m

For first dark fringe

dsin\theta=\frac{\lambda'}{2}\\\Rightarrow \lambda'=2dsin\theta\\\Rightarrow \lambda'=2\times 0.00037066\times sin0.09243\\\Rightarrow \lambda'=1.196\times 10^{-6}\\\Rightarrow \lambda'=1.196\ \mu m

Wavelength of first-order dark fringe observed at this same point on the screen is 1.196 μm

3 0
3 years ago
PLEASE HELP GIVING BRAINLIEST ANSWER
Rasek [7]
Potential energy is an object’s stored energy when it is not moving. Kinetic energy is an object’s energy in motion. You can’t be both moving and not moving at the same time, so PE and KE cannot be equal.
7 0
3 years ago
A 700 g can of beans is dropped from a shelf that is 1.5 m high. What is the gravitational potential energy of this can? Round y
OLga [1]
<span>To find the gravitational potential energy of an object, we can use this equation: GPE = mgh m is the mass of the object in kg g = 9.80 m/s^2 h is the height of the object in meters GPE = mgh GPE = (0.700 kg) (9.80 m/s^2) (1.5 m) GPE = 10.3 J The gravitational potential energy of this can is 10.3 J</span>
4 0
3 years ago
Read 2 more answers
Other questions:
  • Determine the direction of the force (if any) that will act on the charge in each of the following situations. A positive charge
    12·1 answer
  • Doug is driving a golf ball off the tee. His downswing takes 0.50sec from the top of the swing until ball impact. At the top of
    13·1 answer
  • Write at least name of five devices which work under the principles of Physics.
    12·1 answer
  • This is the question with the options
    12·1 answer
  • What are good colleges to attend to become a botanist ??? HELP!!!!!!!!!!!!!
    8·1 answer
  • A circular jogging track forms the edge of a circular lake that has a diameter of 2 miles. Johanna walked once around the track
    14·1 answer
  • Two stones are thrown vertically upward from the ground, one with three times the initial speed of the other. (a) If the faster
    8·1 answer
  • A car with mass 1600 kg drives around a flat circular track of radius 28.0 m. The coefficient of friction between the car tires
    5·1 answer
  • A horse shoe magnet is placed on a mass balance such that a uniform magnetic field of magnitude B runs between it from North to
    8·1 answer
  • A crane lifts an air conditioner to the top of a building. If the building is 12 m high, and the air conditioner has a mass of 2
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!