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3 years ago

Which list correctly describes the usual order of planets inward toward the sun?

Physics

1 answer:

Sati [7]3 years ago

7 0

Option B

Neptune, Uranus, Saturn, Jupiter, Mars, Earth, Venus, Mercury correctly describes the usual order of planets inward toward the sun

<u>Explanation:</u>

Our solar system continues much considerably than the eight planets that revolve around the Sun. The position of the planets in the solar system, commencing inward to the sun is the accompanying: Neptune, Uranus, Saturn, Jupiter, Mars, Earth, Venus, Mercury.

Most next to the Sun, simply rocky material could resist the heat. For this logic, the first four planets: Mercury, Venus, Earth, and Mars are terrestrial planets. The four large outer worlds — Jupiter, Saturn, Uranus, and Neptune: because of their enormous size corresponding to the terrestrial planets. They're also frequently composed of gases like hydrogen, helium, and ammonia preferably than of rocky surfaces.

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Use the f=ma formula to determine your weight in newtons AND pounds on the Moon and Pluto you have a mass of 70.3 kilograms

Julli [10]

Answer:

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6 0

3 years ago

An electron in an atom's orbital shell, labeled X in the model below, released enough energy to move to a different orbital shel

Delicious77 [7]

Answer:

Lower energy shell which will be nearer to the nucleus.

Explanation:

When electron move from one energy level to another, an electron must gain or lose just the right amount of energy.

When atoms releases energy, electrons move into lower energy levels. The electrons in the shells aways from the nucleus have more energy as compared to the electrons in the nearer shells.

Electrons with the lowest energy are found closest to the nucleus, where the attractive force of the positively charged nucleus is the greatest. Electrons that have higher energy are found further away

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3 years ago

Coherent light with wavelength 598 nm passes through two very narrow slits, and the interference pattern is observed on a screen

Stella [2.4K]

Answer:

1.196 μm

Explanation:

D = Screen distance = 3 m

$\lambda$ = Wavelength = 598 m

y = Distance of first-order bright fringe from the center of the central bright fringe = 4.84 mm

d = Slit distance

$tan\theta=\frac{y}{D}\\\Rightarrow \theta=tan^{-1}{\frac{y}{D}}\\\Rightarrow \theta=tan^{-1}{\frac{4.84\times 10^{-3}}{3}}\\\Rightarrow \theta=0.09243\ ^{\circ}$

$sin\theta=\frac{\lambda}{d}\\\Rightarrow d=\frac{\lambda}{sin\theta}\\\Rightarrow d=\frac{598\times 10^{-9}}{sin0.09243}\\\Rightarrow d=0.00037066\ m$

For first dark fringe

$dsin\theta=\frac{\lambda'}{2}\\\Rightarrow \lambda'=2dsin\theta\\\Rightarrow \lambda'=2\times 0.00037066\times sin0.09243\\\Rightarrow \lambda'=1.196\times 10^{-6}\\\Rightarrow \lambda'=1.196\ \mu m$

Wavelength of first-order dark fringe observed at this same point on the screen is 1.196 μm

3 0

3 years ago

PLEASE HELP GIVING BRAINLIEST ANSWER

Rasek [7]

Potential energy is an object’s stored energy when it is not moving. Kinetic energy is an object’s energy in motion. You can’t be both moving and not moving at the same time, so PE and KE cannot be equal.

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3 years ago

A 700 g can of beans is dropped from a shelf that is 1.5 m high. What is the gravitational potential energy of this can? Round y

OLga [1]

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4 0

3 years ago

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