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rusak2 [61]
2 years ago
10

If you throw a ball into the air, Earth exerts a force on the ball. The ball in the air exerts no force on Earth. True or false?

Physics
1 answer:
Lina20 [59]2 years ago
5 0

Answer:

False.

Explanation:

If you throw a ball into the air, Earth exerts a force on the ball. Also, the ball in the air exerts a force on Earth.

This ultimately implies that, there is a force pair between the earth and the ball.

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suppose 384g of steam originally at 100C is quickly cooled to produce liquid water at 31C. How much heat must be removed from th
dlinn [17]

Answer:

Q=977216.256\ J=977.216\ kJ

Explanation:

Given:

  • mass of  steam, m=384\ g
  • temperature of steam, T_{is}=100^{\circ}C
  • temperature of resultant water, T_{fw}=31^{\circ}C

We have,

  • latent heat of vapourization of water, L=2256\ J.g^{-1}
  • specific heat capacity of water, c=4.186\ J.g^{-1}

<em>When we cool the steam of 100°C then firstly it loses its latent heat to convert into water of 100°C and the further cools the water.</em>

<u>Now the heat removed from steam to achieve the final state of water:</u>

\rm Q=latent\ heat\ of\ vapourization+sensible\ heat\ of\ water

Q=m(L+c.\Delta T)

Q=384(2256+4.186\times (100-31))

Q=977216.256\ J=977.216\ kJ

3 0
3 years ago
Suppose the coefficient of static friction between a quarter and the back wall of a rocket car is 0.383. At what minimum rate wo
djverab [1.8K]

Answer:

25.59 m/s²

Explanation:

Using the formula for  the force of static friction:

f_s = \mu_s N --- (1)

where;

f_s = static friction force

\mu_s = coefficient of static friction

N = normal force

Also, recall that:

F = mass × acceleration

Similarly, N = mg

here, due to min. acceleration of the car;

N = ma_{min}

From equation (1)

f_s = \mu_s ma_{min}

However, there is a need to balance the frictional force by using the force due to the car's acceleration between the quarter and the wall of the rocket.

Thus,

F = f_s

mg = \mu_s ma_{min}

a_{min} = \dfrac{mg }{ \mu_s m}

a_{min} = \dfrac{g }{ \mu_s }

where;

\mu_s = 0.383 and g = 9.8 m/s²

a_{min} = \dfrac{9.8 \ m/s^2 }{0.383 }

\mathbf{a_{min}= 25.59 \ m/s^2}

3 0
2 years ago
A 3 kg rock sits on a 0.8 meter ledge. If it is pushed off, how fast will it be going at the bottom?
andrey2020 [161]

As long as it sits on the shelf, its potential energy
relative to the floor is . . .

   Potential energy =      (mass) x (gravity) x (height) =

                                       (3 kg) x (9.8 m/s²) x (0.8m) = <u>23.52 joules</u> .

If it falls from the shelf and lands on the floor, then it has exactly that
same amount of energy when it hits the floor, only now the 23.52 joules
has changed to kinetic energy.

   Kinetic energy =                                          (1/2) x (mass) x (speed)²

                                                 23.52 joules = (1/2) x (3 kg) x (speed)²

Divide each side by  1.5 kg :     23.52 m²/s² = speed²

Take the square root of each side:    speed = √(23.52 m²/s²) =  <em>4.85 m/s </em> (rounded)


6 0
3 years ago
What are the positive impacts of Genetically Modified Crops?
xeze [42]

Answer:

The crops will have the ability to be resistant to certain diseases

7 0
2 years ago
Read 2 more answers
How will the gravitational force on a piece of the surface of the star (m1) by the mass of the rest of the star (m2) (effectivel
kiruha [24]

Answer:

Option B

Explanation:

Gravitational force is a force that attracts two bodies (with a mass) towards each other. If an object has a higher mass, the gravitational pull will be greater.

According to Newton’s inverse square law:

<em>"The gravitational force is inversely proportional to the square of the distance between two bodies."</em>

About this question, the greater the distance between two gravitating bodies, the weaker is the gravitational force between them.

6 0
3 years ago
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