Answer:
0.846 moles.
Explanation:
- This is a stichiometric problem.
- The balanced equation of complete combustion of butane is:
C₄H₁₀ + 6.5 O₂ → 4 CO₂ + 5 H₂O
- It is clear from the stichiometry of the balanced equation that complete combustion of 1.0 mole of butane needs 6.5 moles of O₂ to produce 4 moles of CO₂ and 5 moles of H₂O.
<u><em>Using cross multiplication:</em></u>
- 1.0 mole of C₄H₁₀ reacts with → 6.5 moles of O₂
- ??? moles of C₄H₁₀ are needed to react with → 5.5 moles of O₂
- The number of moles of C₄H₁₀ that are needed to react with 5.5 moles of O₂ = (1.0 x 5.5 moles of O₂) / (6.5 moles of O₂) = 0.846 moles.
Answer:
Explanation:
ok but what is the question
With the info given i would have to say their is no kinetic energy, it's all potential energy.
Answer:
87.27 grams
Explanation:
The mole ratio of nitrogen to hydrogen is 1:3; while that one of hydrogen to the products (ammonia) is 3:2
Thus if 3 moles of hydrogen gas produce 2 moles of ammonia gas
7.7 moles of hydrogen will produce:
(7.7moles×2)/3
77/15 moles
1 mole of ammonia gas has a mass of 14+3=17
since the mass of an atom of nitrogen is 14 while that of hydrogen atom is 1.
Therefore 77/15 moles will have a mass of
77/15 moles × 17=87.27 grams
The answer would be:
D = M/V
D=Density
M= mass
V= volume
