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andre [41]
3 years ago
11

Which of the following describes fertilization?

Chemistry
1 answer:
babymother [125]3 years ago
5 0

Answer: Fertilization defintion

Explanation:

the action or process of fertilizing an egg, female animal, or plant, involving the fusion of male and female gametes to form a zygote.

Or giving rise to new indivisual organisms or offspring and initiating development

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Which stament about energy is mostly correct
klasskru [66]
I would say C is the most correct. 
In D it depends on what water source you're using. Let's say it is a waterfall, then the source of the water (melting ice or a lake) may disappear in the future. 
If you're using underwater "windmills" placed in the ocean, then you would expect it to last a while as the ocean will not disappear in the near future. 
6 0
3 years ago
Pls help! Polonium has a large, unstable nucleus. Through which process is it most likely to become stable?
Stella [2.4K]

The process through which Polonium is most likely to become stable is: B. alpha decay.

An unstable element refers to a chemical element that lose particles because its nucleus contain an excess of internal energy (neutron or proton).

This ultimately implies that, an unstable element is radioactive in nature.

In Science, some examples of an unstable element are:

  • Tritium.
  • Bismuth-209 .
  • Xenon.
  • Polonium.

Polonium is a chemical element with a large, unstable nucleus.

Basically, the most stable isotope of Polonium is Polonium-209, which typically undergoes an alpha decay to form lead-205 and the emission of an alpha particle.

⇒  ^{209}_{84}Po ----> ^{205}_{82}Pb \;+\; ^{4}_{2}\alpha

In conclusion, we can deduce from the above chemical equation that Polonium is most likely to become stable through an alpha decay.

Read more: brainly.com/question/18214726

5 0
3 years ago
Read 2 more answers
1. How are electromagnets similar to other magnets?
Tju [1.3M]

Answer:a As the name suggests, a permanent magnet is 'permanent'. ... An electromagnet is made from a coil of wire which acts as a magnet when an electric current passes through it. Often an electromagnet is wrapped around a core of ferromagnetic material like steel, which enhances the magnetic field produced by the coil.... hope these helps chu :/

Explanation:

8 0
3 years ago
How much energy is used to melt 44.33 g of solid oxygen?
Nutka1998 [239]

Answer:

Q1 = C * m * dT

Q2 = Qm * m

Qtotal = Q1 + Q2

Q1 - is amount of energy you need to apply to heat oxygen from the current temperature till you reach the melting temperature. Only if the oxygen is below to melting temperature.

C - is calorific capacity of oxygen -- better look at tables, it is a constant value

m - is the amount of oxygen, we will use moles because the other data shows moles, but could be grams, kg, etc.

dT - is the diference of temperatures between the current and the melting one. The melting temperature is constant and you can find it on tables, then (Tm - To)

Q2 is the amount of energy you have to add to melt oxygen once the oxygen has reached the melting temperature (Tm)

Qm is a constant value you could find on tables, depends on the mass of oxygen and is due to internal processes as changes in atomic distributions

If the oxygen is initially at melting temperature (melting point) you only need to know Q2, as dT = 0

I will do an example for you, but in future you should provide data of constants, it takes very long to find them in books or internet.

Data from tables

Tm =  54.36 K

C = 29.378 J/mol K this is at 25 C (or 298 K), is not really correct, you should look at its value at less than 54.36 K, but you can use it here.

Qm = 0.444 kJ/mol

Problem -- you have 44.33g of Oxygen -- Molecular weight of O2 is 32 g/mol

So you have 44.33/32 = 1.385 moles of oxygen

a) if oxygen is already at melting temperature: you only have to melt it

Qtotal = Q1 + Q2 = [0 (dT = 0) + Qm * m] = 0.444 * 1.385 = 0.615 kJ = 615 J

b) supposing an initial temperture of 50 K: now you have to heat oxygen till melting temperature and then melt it.

Q1 = C * m * dT = 29.378 * 1.385 * (54.36 - 50) = 177.442 J

Q2 = Qm * m = 615 J

Qtotal = 177.442 + 615 = 792.44 J

Explanation:

4 0
3 years ago
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90 grams of NaNO3 were added to solution at 10 degrees Celsius. What type of solution was formed?
vichka [17]

Answer:

friend me on here and imma send you the link Explanation:

4 0
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