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Ronch [10]
3 years ago
15

A small 20-kilogram canoe is floating downriver at a speed of 2 m/s. What is the canoe's kinetic energy?

Physics
2 answers:
MariettaO [177]3 years ago
8 0
Ek=1/2mv^2 = (20)(1/2)(2x2) =40
Novosadov [1.4K]3 years ago
5 0

Answer: 40 Joules

Explanation: Kinetic energy is the energy possessed by a body by virtue of its motion.

Kinetic energy depends on the mass and speed of the object.

K.E=\frac{1}{2}\times mv^2

m= mass of canoe = 20 kg

v= speed of canoe = 2 m/s

K.E=\frac{1}{2}\times 20kg\times (2m/s)^2

K.E=40kgm^2s^-{2}=40Joules

(1kgm^2s^{-2}= 1Joule)

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An open rectangular tank 1 m wide and 2 m long contains gasoline to a depth of 1 m. If the height of the tank sides is 1.5 m, wh
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Answer:

a_y = 4.9\ m/s^2

Explanation:

Given,

Width of rectangular tank, b = 1 m

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height of the tank, d = 1.5 m

Depth of gasoline on the tank, h = 1 m

\dfrac{dz}{dy}=-\dfrac{1.5-1}{1}

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The differential form with the acceleration

\dfrac{dz}{dy}=\dfrac{-a_y}{a_z + g}

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0.5=\dfrac{a_y}{0 + 9.8}

a_y = 9.8\times 0.5

a_y = 4.9\ m/s^2

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