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svetoff [14.1K]
3 years ago
10

How many seconds will it take for a the International Space Station to travel 450 km at a rate of 100 m/s?

Physics
1 answer:
SVEN [57.7K]3 years ago
8 0

Time = (distance) / (speed)

<em></em>

Time = (450 km) / (100 m/s)

Time = (450,000 m) / (100 m/s)

Time = <em>4500 seconds </em>(that's 75 minutes)

Note:

This is about HALF the speed of the passenger jet you fly in when you go to visit Grandma for Christmas.

If the International Space Station flew at this speed, it would immediately go ker-PLUNK into the ocean.

The speed of the International Space Station in its orbit is more like 3,100 m/s, not 100 m/s.

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a log splitter puts out 1 100W of power for every 1500 W put into it. the efficiency of the machine is what
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Sally Leadfoot was pulled over on her way from Syracuse to Ithaca by an officer claiming she was speeding. The speed limit is 65
Citrus2011 [14]

Sally's average speed is <u>35.3 mi/h.</u>

Average speed of a body is the total distance traveled in the given time interval.

Express the distance  d traveled in miles.

d=\frac{97 km}{1.6 km/m\\i} \\ = 60 mi

Express the time t traveled in hours.

t  =\frac{102 min}{60 min/hr}\\ = 1.7 h

Calculate the average speed v.

v =\frac{d}{t} \\ =\frac{60 mi}{1.7h} \\   = 35.3 mi/h

Her average speed is 35.3 mi/h, which is less than the speed limit of 65 mi/h.

However, the average speed of an object is different from its instantaneous speed. It could be possible that at the time when the officer apprehended her, Sally could have been travelling at a speed greater than the prescribed speed limit, which would have prompted the officer to issue a speeding ticket to her.

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3 0
3 years ago
What is the equation for finding the amount of inertia in forces and motion? Explain how you solve that equation.​
jolli1 [7]

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4 0
2 years ago
20 POINTS 20 POINTS On a bright sunny day you decide to take a walk. You begin at your home and walk 1000 meters to an ice cream
Kay [80]

Answer:

A) Total Distance = 2000 m and Total displacement = 0 m

B) Average Speed = 44.44 m/min and Average Velocity = 0 m/min

C) Average Speed = 0.7407 m/s and Average velocity = 0 m/s

Explanation:

A) Distance to reach ice cream shop from home = 1000 meters

Therefore distance to get back home would also be 1000 meters.

Total distance traveled = 1000 + 1000 = 2000 metres

Since journey started at home and ended at home, then total displacement = 0 metres.

B) Average speed = Total distance/total time.

Total time = 10 + 15 + 20 = 45 minutes

Since total distance = 2000 m

Then;

Average speed = 2000/45

Average speed = 44.44 m/min

Average velocity = Total displacement/total time

Average velocity = 0/45 = 0 m/min

C) We now want answers in B to be in m/s.

Total time = 45 minutes.

From conversion, 60 seconds make 1 minute. Thus, 45 minutes = 45 × 60 = 2700 seconds

Thus;

Average Speed = 2000/2700

Average Speed = 0.7407 m/s

Average displacement = 0/2700 = 0 m/s

4 0
3 years ago
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