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3 years ago

How many seconds will it take for a the International Space Station to travel 450 km at a rate of 100 m/s?

Physics

1 answer:

SVEN [57.7K]3 years ago

8 0

Time = (distance) / (speed)

Time = (450 km) / (100 m/s)

Time = (450,000 m) / (100 m/s)

Time = <em>4500 seconds </em>(that's 75 minutes)

Note:

This is about HALF the speed of the passenger jet you fly in when you go to visit Grandma for Christmas.

If the International Space Station flew at this speed, it would immediately go ker-PLUNK into the ocean.

The speed of the International Space Station in its orbit is more like 3,100 m/s, not 100 m/s.

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A wye-connected load has a voltage of 480v applied to it. What is the voltage drop across each phase

rodikova [14]

Answer:

$Y_A=277.128 \angle 30v$

$Y_B=277.128 \angle (-150)v$

$Y_C=277.128 \angle (90)v$

Explanation:

From the question we are told that

Voltage $V_L_L =480v$

Generally in a case of Y_connection $V_p_ h$ is mathematical represented as

$V_p_h=\frac{V_l_l}{\sqrt{3}} \angle (\phi-30)v$

Generally voltage drop across phase A

$Y_A=\frac{408}{\sqrt{3}} \angle -(0-30)$

$Y_A=277.128 \angle 30v$

Generally voltage drop across phase B

$Y_B=277.128 \angle (-30-120)$

$Y_B=277.128 \angle (-150)v$

Generally voltage drop across phase C

$Y_C=277.128 \angle (-30+120)$

$Y_C=277.128 \angle (90)v$

3 0

3 years ago

The bell rings and a physics student heads to class. They stop to talk to a few friends. They slow

grin007 [14]

Answer:

420m

Explanation:

Given parameters:

Time = 5minutes

Average speed = 1.4m/s

Unknown:

Distance covered = ?

Solution:

Speed is the rate of change of distance with time.

Mathematically;

Speed = $\frac{distance}{time}$

Distance = speed x time

Insert the parameters and solve;

Convert the time to seconds;

1 minute = 60s

5 minute = 5 x 60 = 300s

So,

Insert the parameters and find the distance;

Distance = 300 x 1.4 = 420m

3 0

3 years ago

The force acting between two charged particles a and b is 5.2 x 10^-5 newtons. Charges a and b are 2.4 x 10^-2 apart. If the cha

Aneli [31]

4.62x10^-11
hope this helped!

5 0

4 years ago

A force of 100 N is applied to a crate at an angle of 60° to the horizontal surface.

ad-work [718]

Answer:

100 J

Explanation:

Given:

Force acting on the crate is, $F=100\ N$

Displacement of the crate is, $S=2\ m$

Angle between the direction of force and displacement is, $\theta=60\°$

Now, work done by a force 'F' causing a displacement 'S' such that the angle between the force and displacement is $\theta$ is given as:

$Work=F\times S\times \cos\theta$

Now, plug in 100 N for 'F', 2 m for 'S', and 60° for $\theta$ . This gives,

$Work=(100\ N)(2\ m)(\cos(60))\\\\Work=(200\times 0.5)\ \textrm{N-m}\\\\Work=100\ J$

Therefore, the work done by the force is 100 J.

8 0

4 years ago

What is parallelogram law of vector addition ???

Vladimir [108]

Answer:

According to the parallelogram law of vector addition if two vectors act along two adjacent sides of a parallelogram(having magnitude equal to the length of the sides) both pointing away from the common vertex, then the resultant is represented by the diagonal of the parallelogram passing through the same common vertex

Explanation:

6 0

3 years ago