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2 years ago

6

Michael will spend at most $30 on gifts. So far, he has spent $14. What are the possible additional amounts he will spend? Use c

for the additional amount (in dollars) Michael will spend.
Write your answer as an inequality solved for c.

1 answer:

Stolb23 [73]2 years ago

6 0

Answer:

Step-by-step explanation:

By itself: 32 < 17+cSolved: 15 < cIf wanted it to be solved:32 < 17 + c-17 -1715 < c

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5. Solve for x using any method you'd like. Round to the hundredth. Show all your work. (2 points each) d. 20x^3 = 7x^5

Sindrei [870]

Solving this equation for x, we have:

$\begin{gathered} 20x^3=7x^5 \\ 7x^5-20x^3=0 \\ x^3(7x^2-20)=0 \\ \begin{cases}x^3=0\to x=0 \\ 7x^2=20\to x=\pm\sqrt[]{\frac{20}{7}}\end{cases} \end{gathered}$

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1 year ago

Jeremy bought postcards on a trip. He

noname [10]

Answer:

T = total #

T = 5 (to the aunt) + 1/2 (T - 5) (to his friends) + 1 (to his sister) + 4 (left)

T = 5 + 1/2 (T - 5) + 1 + 4

T = 10 + 1/2 (T - 5)

2T = 20 + (T - 5)

2T = 20 + T - 5

2T = 15 + T

T = 15

Step-by-step explanation:

5 0

3 years ago

Simplify the expression using properties of exponents.<br><br> 12a-9b-4<br><br> 9a2b6

Free_Kalibri [48]

Check out -m-a-t-h-w-a-y-.-c-o-m- (This helps a lot!)

5 0

3 years ago

AveGali [126]

Answer:

Total time taken by walking, running and cycling = 22 minutes.

Step-by-step explanation:

Let the speed of walking = x

As given,

The distance of walking = 1

Now,

As $Time = \frac{Distance }{Speed}$

⇒ Time traveled by walking = $\frac{1}{x}$

Now,

Given that - He runs twice as fast as he walks

⇒Speed of running = 2x

Also given distance traveled by running = 1

Time traveled by running = $\frac{1}{2x}$

Now,

Given that - he cycles one and a half times as fast as he runs.

⇒Speed of cycling = $\frac{3}{2}$ (2x) = 3x

Also given distance traveled by cycling = 1

Time traveled by cycling = $\frac{1}{3x}$

Now,

Total time traveled = Time traveled by walking + running + cycling

= $\frac{1}{x}$ + $\frac{1}{2x}$ + $\frac{1}{3x}$

= $\frac{6+3+2}{6x} = \frac{11}{6x}$

If he cycled the three mile , then total time taken = $\frac{1}{3x}$ + $\frac{1}{3x}$ + $\frac{1}{3x}$ = x

Given,

He takes ten minutes longer than he would do if he cycled the three miles

⇒x + 10 = $\frac{11}{6} x$

⇒ $x - \frac{11}{6} x = -10$

⇒ $-\frac{5}{6}x = -10$

⇒x = $\frac{60}{5}$ = 12

⇒x = 12

∴ we get

Total time traveled by walking + running + cycling = $\frac{11}{6} x = \frac{11}{6} (12) = 11 (2) = 22$ min

7 0

3 years ago

In a particular year, a total of 50,127 students studied in two of the most popular host countries when traveling abroad. If 838

Arlecino [84]

Answer:

In the most popular abroad country: 29,255 students

In the second-most one: 20,872 students

Step-by-step explanation:

Let's write the situation in an equation to help us solve this. X represents the amount of students in the second most popular country. So we know that in total, there's 50,127 students so let's make an equation that equals this. ???????=50,127. As we know, the most popular country has 8383 more students than the second one so we can write it as x+8383 and for the second most popular country, we can write it as x. We know that both of the countries students combined equal 50,127 students so we have our equation. (x)+(x+8383)=50,127 students. After solving the equation, you get x=20, 872. As we know x=the amount of students in the second most popular country which means there's 20,872 students in the second one. Additionally, for the first most popular one, the equation for the amount of students in it is x+8383 so..... 20,872+8383=Total number of students in the most popular one which is 29,255 students.

7 0

3 years ago