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Mnenie [13.5K]
3 years ago
9

The thermal efficiency of two reversible power cycles operating between the same thermal reservoirs will a)- depend on the mecha

nisms being used b)- be equal regardless of the mechanisms being used c)- be less than the efficiency of an irreversible power cycle
Engineering
1 answer:
mestny [16]3 years ago
4 0
C ,, i’m pretty sure .
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A.

The power generated by a wind farm is not constant because of irregular wind patterns.

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Argue the importance to society of incorporating green building into an engineer's designs, with at least two examples.
stellarik [79]

Answer:

Green Design is your answer

Explanation:

4 0
2 years ago
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Please help i am give brainliest i really need help guys no links please ???
devlian [24]

Explanation:

The wind is an actual form of solar energy. winds are caused by the heating of the atmosphere by the sun, the rotation of the earth, and the earth's surface irregularities. The wind is capture in a wind turbine which provides a renewable energy source, the wind makes the rotor spin, as the rotor spins the movement of the blades drives a generator that creates energy, also known as wind power. The average wind efficiency of turbines is between 35-45%.

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4 0
3 years ago
Railroad tracks made of 1025 steel are to be laid during the time of year when the temperature averages 4C (40F). Of a joint spa
DENIUS [597]

Answer:

41.5° C

Explanation:

Given data :

1025 steel

Temperature = 4°C

allowed joint space = 5.4 mm

length of rails = 11.9 m

<u>Determine the highest possible temperature </u>

coefficient of thermal expansion ( ∝ ) = 12.1 * 10^-6 /°C

Applying thermal strain ( Δl / l )  = ∝ * ΔT

                                    ( 5.4 * 10^-3 / 11.9 )  = 12.1 * 10^-6 * ( T2 - 4 )

∴  ( T2 - 4 ) =  ( 5.4 * 10^-3 / 11.9 ) / 12.1 * 10^-6

hence : T2 = 41.5°C

8 0
3 years ago
Air enters the 1 m² inlet of an aircraft engine at 100 kPa and 20° C with a velocity of 180 m/s. Determine: a) The volumetric fl
Shkiper50 [21]

Answer:

a) 180 m³/s

b) 213.4 kg/s

Explanation:

A_1 = 1 m²

P_1 = 100 kPa

V_1 = 180 m/s

Flow rate

Q=A_1V_1\\\Rightarrow Q=1\times 180\\\Rightarrow Q=180\ m^3/s

Volumetric flow rate = 180 m³/s

Mass flow rate

\dot{m}=\rho Q\\\Rightarrow \dot m=\frac{P_1}{RT} Q\\\Rightarrow \dot m=\frac{100000}{287\times 293.15}\times 180\\\Rightarrow \dotm=213.94\ kg/s

Mass flow rate = 213.4 kg/s

3 0
3 years ago
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