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alexdok [17]
3 years ago
14

Do you think the mining process is faster when you know in advance that the land must be restored? Explain.

Engineering
1 answer:
vfiekz [6]3 years ago
3 0

Answer: No, the mining process isn't faster when you know in advance that the land must be restored.

Explanation:

The mining process would be slower when mining companies know in advance that the land must be restored because they have to be more careful about their impact on the environment & avoid taking unnecessary damage to ruin the land which they know they must restore.

So, it's evident how this would slow down the mining process. If there were no obligations to restore land, the mining companies would just come at the mining space and run their mining process fast without big concerns for the consequences.

But the caution definitely slows them down.

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A HSS152.4 × 101.6 × 6.4 structural steel [E = 200 GPa] section (see Appendix B for crosssectional properties) is used as a colu
Temka [501]

Answer:

(a) 126.66 kN (b) 31.665 kN (c) 258.49 kN (d) 506.64 kN

Explanation:

Solution

Given

A HSS152.4 × 101.6 × 6.4 structural steel is used as a column

Actual length of the column , L= 6 m

The elasticity modules, E = 200 GPa

The factor of safety with respect to failing buckling . F.S =2

Geometric properties  of structural steel shapes for, A HSS152.4 × 101.6 × 6.4

the moment of inertial about y axis Iy =4 .62 * 10^ 6 mm ^4

For

(a)  If the end condition is pinned - pinned

The effective  length factor, K =1

The critical buckling load , Pcr = π²EI/(KL)²

Pcr = π² * 200 * 10 ^3 * 4.62 * 10 ^6/( 1* 6* 10 ^3)

= 253319.85N

= 253.32N

The maximum safe load , Pallow = 253.32 /2 = 126.66kN

hence, the maximum safe for the column is 126.66kN

(b)If the end condition is  fixed free-free

the effective length factor, K= 2

The critical buckling load , Pcr = π²EI/(KL)²

Pcr = π² * 200 * 10 ^3 * 4.62 * 10 ^6/( 2 * 6 * 10 ^3)²

= 63329.96N

=63.33kN

The maximum safe load,  P allow = Pcr/F.S

P allow = 63.33/2

31.665 kN

Therefore the maximum safe for the column is 31.665 kN

(c) If the end condition is fixed- pinned

The effective  length factor K =0.7

The critical buckling load , Pcr = π²EI/(KL)²

Pcr = π² * 200 * 10 ^3 * 4.62 * 10 ^6/( 0.7 * 6 * 10 ^3)²

=516979.2 8N

=516.98 kN

The maximum safe load,  P allow = Pcr/F.S

P allow = 516.98 kN/2

=258.49 kN

Therefore the maximum safe for the column is 258.49 kN

(d) If the end condition is fixed -fixed

The effective factor, K =0.5

The critical buckling load , Pcr = π²EI/(KL)²

Pcr = π² * 200 * 10 ^3 * 4.62 * 10 ^6/( 0.5 * 6 * 10 ^3)²

=1013279.4 N

=1013.28 kN

The maximum safe load,  P allow = Pcr/F.S

P allow = 1013.28 / 2

= 506.64 kN

P allow = 506.64 kN

Therefore the maximum safe for the column is 506.64 kN

8 0
4 years ago
Does anyone know obamas last name???? please help its for a friend I swear!!!111!!11!
ANTONII [103]

Answer:

Explanation:

Barack Hussein Obama

6 0
3 years ago
Planetary gears require the armature to be offset via a gear housing that holds the starter drive.
Yuri [45]

Answer: Due to the way that spur gears work, starters that use them require an offset armature, which is achieved by placing the starter drive in separate gear housing. In starters that use planetary gears, the gears can be contained in an in line drive-end housing.

Explanation: true

6 0
3 years ago
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You wish to design a cantilever beam with a square cross section and length L that can support an end load of F without yielding
koban [17]

Answer:

with a square cross section and length L that can support an end load of F without yielding. You also wish to minimize the amount the beam deflects under load. What is the free variable(s) (other than the material) for this design problem?

a. End load, F.

b. Length, L.

c. Beam thickness, b

d. Deflection, δ

e. Answers b and c.

f. All of the above.

8 0
3 years ago
Which of the following is not a task electricians typically do when maintaining a building’s electrical system?
Scorpion4ik [409]

Answer:replace insulation to help control...

Explanation:

Thats a insulation workers job

4 0
3 years ago
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