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frosja888 [35]
2 years ago
11

X

Mathematics
1 answer:
Rufina [12.5K]2 years ago
3 0
The answer is 20 because it is 20
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Find two angles (in radians) whose sine ratio is...
frutty [35]

Hi there!

\large\boxed{\frac{\pi}{3} \text{ and } \frac{2\pi}{3}}

From the unit circle, we can locate the two values of sine Ф (y-value of the coordinate)  at which sin Ф = √3/2.

The two values are Ф = π/3 and 2π/3.

8 0
3 years ago
A company makes t-shirts and their research shows that that price and demand are related linearly: p = m x + b . They know that
allsm [11]

Answer:

The linear equation relating price to demand is Q=-0.5*P + 30

Step-by-step explanation:

The demand for a good is the quantity of that good that the demanders are willing to purchase at a given price.

Then, the Demand Curve relates the quantity that a consumer would be willing to buy as a function of price.

You seek to determine the linear equation that relates the price to the demand Q = m * P + b where Q is the quantity demanded at a price P, and compared with the equation of the straight line y = mx + b, m is the slope and b is the ordinate to the origin.

On a line of the form y = m * x + b, the value of m, having two points, is calculated by:

m=\frac{y2-y1}{x2-x1}

And the ordinate to the origin b is calculated, taking the value of m, replacing any of the two points (replacing any of the two because it must give the same value of b) in the expression y = m * x + b and solving its value.

In the case of Q=m*P+b, the value of m, having two points, is calculated by:

m=\frac{Q2-Q1}{P2-P1}

Being:

  • Q1= 5
  • P1= $50
  • Q2= 10
  • P2= $40

and replacing:

m=\frac{10-5}{40-50}

you get:

m= -0.5

So, being Q=-0.5*P+b,  b is calculated by:

  • Replacing the point Q1= 5 and P1= 50

5= -0.5*50 + b → 5= -25 + b → 5+25= b → b= 30

  • Replacing the point Q1= 10 and P1= 40

10= -0.5*40 + b → 10= -20 + b → 10+20= b → b= 30

Then, <u><em>the linear equation relating price to demand is Q=-0.5*P + 30</em></u>

8 0
3 years ago
What is the value of 3x2 - 5xy + 5y2 for x = -6 and y = 2?
crimeas [40]
Answer is 188 3x2 - 5xy + 5y2 Now put x = -6 and y = 2 3(-6)2 - 5(-6)(2) + 5(2)2 3(36) - 5(-12) + 5(4) 108 + 60 + 20 188
4 0
4 years ago
Write 108.92 in expanded form
Kitty [74]
Sorry if my writing is sloppy

5 0
3 years ago
PLEASE HELPPPPPP!!!!!!Solve this system of linear equations separate the x-and y-values with a comma
GenaCL600 [577]

Answer:

x=-6,\\y=6

Step-by-step explanation:

Rewrite the system of equations as:

\begin{cases}-13x+2y=90\\-6x+2y=48\end{cases}

Subtract the second equation from the first to isolate x:

-13x+2y-(-6x+2y)=42,\\-7x=42, \\\fbox{$x=-6$}

Plug in x=-6 into any of the equations above and solve for y:

-6(-6)+2y=48,\\2y=12,\\\fbox{$y=6$}

Verify that the solution pair (-6, 6) works \checkmark

Therefore, the solution to this system of equations is:

x=-6,\\y=6

8 0
3 years ago
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