Equivalent expression is the expression of two equation when the way of representation of the two equation is different but the result is same.The expressions which are equivalent to the given expression are,
Given information-
The expression given in the problem is,

<h3>Equivalent expression-</h3>
Equivalent expression is the expression of two equation when the way of representation of the two equation is different but the result is same.
For given expression,

As the above function is the function of <em>x. </em>Thus it can be written as,

<h3>Logarithm power rule</h3>
Logarithm power rule states that the exponent of the logarithm function can transfers to front of the logarithm and vice versa. Thus,

Now the value of
is equal to the zero. Thus,

Hence the expressions which are equivalent to the given expression are,
Learn more about the equivalent expression here;
brainly.com/question/10628562
Given that <span>For
a certain model of car the distance

required to stop the vehicle if
it is traveling at

mi/h is given by the formula
![d=v+\frac{v^2}{20}, where [tex]d](https://tex.z-dn.net/?f=d%3Dv%2B%5Cfrac%7Bv%5E2%7D%7B20%7D%2C%20where%20%5Btex%5Dd%20)
is measured in feet.
If Kerry wants her stopping distance not to exceed 75
ft, then the range of speeds (in mi/h) can she travel is obtained as follows:

Therefore, the range of speed she can travel is

</span>
Hi ;-)
10 minutes for 2 songs = 5 minutes per song
10 : 2 = 5
Answer:
52degrees
Step-by-step explanation:
Let the measure of the largest angle be x
middle angle be y
smallest angle be z
Since the sum of angle in a triangle is 180 degrees, hence;
x + y + z = 180 .... 1
If the measure of the largest angle is 32 less than 3 times the smallest angle, then;
x = 3z - 32
3z = x+ 32
z = x+32/3 ..... 2
If he measure of the middle angle is 8 more than half the measure of the largest angle, then;
y = x/2 + 8 .... 3
Substitute 2 and 3 into 1;
x + x/2 + 8 + (x+32)/3 = 180
multiply through by 6
6x + 3x + 48 + 2(x+32) = 1080
9x + 48 + 2x + 64 = 1080
11x + 112 = 1080
11x = 1080-112
11x = 968
x = 968/11
x = 88 degrees
Get the middle angle y;
Since y = x/2 + 8
y = 88/2 + 8
y = 44 + 8
y = 52 degrees
Hence the measure of the middle angle is 52degrees