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Paul [167]
3 years ago
12

There are 5 balls, 3 red, and 2 black. What is the probability that a random ordering of the 5 balls does not have the 2 black b

alls next to each other
Mathematics
1 answer:
Molodets [167]3 years ago
8 0

Answer:

there are 6 different ways they will not be next to each other

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stiks02 [169]

Answer:

\begin{bmatrix}\mathrm{Solution:}\:&\:x\ge \:0\:\\ \:\mathrm{Interval\:Notation:}&\:[0,\:\infty \:)\end{bmatrix}

\begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)=1\:\\ \:\mathrm{Interval\:Notation:}&\:f\left(x\right)=1\end{bmatrix}

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Least to greatest 3.06, 3.8, 3 1/6, 3 3/4
nadya68 [22]
3.06, 3 1/6, 3 3/4, 3.8.

Hope that helps.
7 0
2 years ago
If dab=125 what is the measure of cba justify your reasoning
KonstantinChe [14]
The answer is <span>D. x=y-z-9/7</span>
8 0
3 years ago
Whats the answer giving brainliest answer
stiks02 [169]

Answer:

C because its the only one that fits the question its asking. 12-6 8-4 4-2

Step-by-step explanation:

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3 years ago
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Step-by-step explanation:

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